- #1
popo902
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Homework Statement
Using polar coordinates, evaluate the integral which gives the area which lies in the first quadrant between the circles
x^2 + y^2 = 4
and
x^2 - 2x + y^2 = 0
Homework Equations
The Attempt at a Solution
for my integral i got
0<= theta <=pi/2 for the theta bounds since it lies in the 1st quad
and i got
2costheta<= r <= 2 for the bounds of r because 2costheta is the polar version of
x^2 - 2x + y^2 = 0 and 2 is 'r' in the equation x^2 + y^2 = 4
and the equation that i integrated is (2- 2costheta)r
you add the extra r when turning the equation polar and the equation r=2 is over
r = costheta when i graphed it
and welll...
i got pi - 3 but it's wrong...
am i even setting up the equation right or am i just having problems with the math?