- #1
franky2727
- 132
- 0
got a question here saying first to find the equlib points of the system xdot=x(x+1) so there obviously 0 and -1
then part 2 is draw the trajectory in the x-xdot plane
the answers are increasing above 0 decreasing between -1 and 0 and increasing at <-1 again for obvious reasons. then i am asked to discuss the nature of the equlibrium points, don't remember doing this and I've lost all of my notes for this topic, it states that the x=0 point is unstable and the x=-1 point is asemptoticaly (i think that's the word) stable, could someone please explain this area, where it comes from and also the other possible answers apart from the 2 above for different situations, thanks
then part 2 is draw the trajectory in the x-xdot plane
the answers are increasing above 0 decreasing between -1 and 0 and increasing at <-1 again for obvious reasons. then i am asked to discuss the nature of the equlibrium points, don't remember doing this and I've lost all of my notes for this topic, it states that the x=0 point is unstable and the x=-1 point is asemptoticaly (i think that's the word) stable, could someone please explain this area, where it comes from and also the other possible answers apart from the 2 above for different situations, thanks