Yea I am, I tried integrating and it got really messy, I assumed I was doing something wrong and instead assumed that potential is constant and hence e field is 0.Simon Bridge said:You can check by considering that the electric field is a vector... the field dead center is easy, you are wondering about off-center right?
If you show what you did, perhaps we can help ?yeezyseason3 said:I tried integrating and it got really messy
The electric field inside a charged ring is a measure of the force exerted on a charged particle placed within the ring. It is a vector quantity that describes the direction and magnitude of the force at any given point inside the ring.
The electric field inside a charged ring can be calculated using Coulomb's law, which states that the force between two charged particles is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.
The strength of the electric field inside a charged ring depends on the charge of the ring, the distance from the center of the ring, and the size of the ring.
No, the electric field inside a charged ring is not uniform. It is stronger near the inner edge of the ring and weaker near the outer edge. This is because the charges in the ring are closer together near the inner edge, leading to a stronger electric field.
The electric field inside a charged ring and a charged disc are similar in that they both have a central point where the electric field is strongest. However, the electric field inside a ring is stronger near the inner edge, while the electric field inside a disc is constant throughout.