Electric Flux of Two Hemispheres with different radii

In summary, two hemispherical surfaces, 1 and 2, of respective radii r1 and r2, are centered at a point charge and are facing each other to form an annular ring (surface 3). The electric field at position r⃗ due to the point charge is given by E⃗ (r⃗ )=C/r^2 r_hat, where C is a constant proportional to the charge, r=∣∣r⃗ ∣∣, and r_hat=r⃗ /r is the unit vector in the radial direction. The angle between the area vector and electric field vector is 90 degrees, leading to 0 electrical flux through surface
  • #1
Inveritatem
6
0

Homework Statement


Two hemispherical surfaces, 1 and 2, of respective radii r1 and r2, are centered at a point charge and are facing each other so that their edges define an annular ring (surface 3), as shown.

1006820_01.jpg

Homework Equations


The field at position r⃗ due to the point charge is:

E⃗ (r⃗ )=C/r^2 r_hat

where C is a constant proportional to the charge, r=∣∣r⃗ ∣∣, and r_hat=r⃗ /r is the unit vector in the radial direction.

The Attempt at a Solution


The hints imply that because the electric field lines everywhere are parallel to the annular ring (surface 3), the angle between the area and electric field vector is 90, which implies that the flux through surface 3 is 0. I am confused as to why this is the case, as looking at the picture I only see one possibility:

From the side view, the electric field lines seem to only go through surface 1, meaning no electric field passes the surface of surface 3, which leads to 0 electrical flux.

Can anyone help explain why there are electrical field lines that form a 90 degree angle with the area vector?
 
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  • #2
Inveritatem said:
Can anyone help explain why there are electrical field lines that form a 90 degree angle with the area vector?
Be sure you understand the convention for the direction of an area vector.

In the side view picture, pick any point on surface 3 and draw the area vector for a small patch of area at that point. Also draw the direction of the field at that point.

EDIT: I think the confusion is with the wording of the hint. It should have said the the angle between the area vector and the electric field vector is 90o.
 
Last edited:

1. What is electric flux?

Electric flux is a measure of the flow of an electric field through a given surface. It is represented by the Greek letter Phi (Φ) and is measured in units of volts per meter (V/m).

2. How is electric flux calculated?

Electric flux is calculated by multiplying the strength of the electric field by the area of the surface that the field passes through. It is also dependent on the angle between the electric field and the surface, as well as the shape of the surface.

3. What are two hemispheres with different radii?

Two hemispheres with different radii refer to two half-spheres with different sizes. This can be visualized as a small hemisphere sitting on top of a larger one, or two hemispheres of different sizes overlapping each other.

4. How does the radius of a hemisphere affect its electric flux?

The radius of a hemisphere directly affects its electric flux. The larger the radius, the greater the surface area and therefore, the higher the electric flux. This is because a larger surface area allows for more electric field lines to pass through, resulting in a higher electric flux.

5. Can the electric flux of two hemispheres with different radii be equal?

Yes, it is possible for the electric flux of two hemispheres with different radii to be equal. This can occur if the electric field strength and the angle between the electric field and the surface are the same for both hemispheres, despite their different sizes.

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