Entanglement and teleportation

In summary: Entanglement is a very strong connection between particles, but it doesn't mean that information is always transmitted instantly. Information can take some time to propagate.
  • #106
Sherlock said:
If by "they" you mean the opposite-moving disturbances ...
well, nobody knows what they share or don't share. But,
the assumption is that they do share some physical property
or properties. That's what entanglement is all about.
Great care is taken to produce the shared properties
experimentally.

Keep in mind that QM is about the measurement results, not
the opposite-moving disturbances.

As Vanesch states, it sounds as if you don't understand Bell/Aspect (or perhaps deliberately choose to ignore it). We do understand a lot about entanglement, and that is that the entangled particles are in a superposition of states until they are observed. During that time, they do not have well defined physical properties - but they nonetheless share the same wavefunction perfectly. Further, the assumption you describe has been falsified by experiment IF by physical property you mean properties with definite values (hidden variables).
 
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  • #107
vanesch said:
I wonder (really no offense intended) if you understood the implications of Bell's theorem, then. Indeed, the above situation is EXACTLY what Einstein thought was "really" happening, and about which Bell wrote his famous theorem. The "shared properties" are simply the "hidden variables". Well, it turns out - that's the entire content of Bell's theorem - that of course these shared properties can give rise to correlations in the observation (that's no surprise), but that correlations obtained that way SATISFY CERTAIN NON-TRIVIAL INEQUALITIES. Guess what ? Quantum theory's predictions violate those inequalities (and seem to be confirmed by experiment - under some *very* reasonable extra assumptions).

No offense taken.:) If I'm wrong in how I'm thinking about
this, then I don't mind being wrong sort of in a similar
way to Einstein.:) But, I don't think he was wrong, essentially.
I don't think that experimental violations of Bell inequalities
mean what a lot of people say they mean.

vanesch said:
The hypothesis Bell started with was the following: correlations between probabilitic events can only have two different causes ; otherwise their randomness is independent. These two causes are: a) direct causal influence (meaning: what happens at A has a direct influence of what happens at B), or b) common origin of causes.
This is in fact a universally accepted idea (which turns out to be false in quantum theory), and most "common sense" judgements take it implicitly for granted. In fact, many people forget about the B option, which leads to a lot of nonsense (especially in politically colored studies), but Bell didn't of course.

Let us consider the following study: carefull investigation has led us to find out a remarkable correlation:there is a correlation between "driving a Jaguar" and "having a Rolex", which means that if P_j is the probability for someone to drive a Jaguar (quite low) and P_r is the probability for someone to have a Rolex (also quite low) and P_rj is the probability for someone to drive a jaguar and to have a rolex, then P_rj is bigger than P_r x P_j (which would be the case if there was no correlation).

You mean? ... P_j is the probability for someone to drive
a Jaguar and *not also* have a Rolex, and P_r is the probability
for someone to have a Rolex and *not also* drive a Jaguar.
P_rj > (P_r)(P_j), so P_r and P_j are not correlated wrt each
other.

Just like in the EPR-Bell experiments where P(A) and
P(B) aren't correlated wrt each other. :)

(I snipped some stuff)

Ok, the effort is appreciated. :) Here's my
view.

We're analyzing the entanglement. The assumption
is that the entanglement is due to common
properties imparted via common emission event.
In effect, the same light extending from polarizer
to polarizer. We're asking, in effect, to
what degree is it true that the light incident
on the polarizers is the same at A and B for
any set of joint measurements.

You wouldn't write this as,
P(A,B) = (cos^2 |a - L|) (cos^2 |b - L|)

Given our initial assumption, and the
observational context. we wouldn't expect
P(A,B) to be the correlation of P(A) and P(B)
wrt each other. Nor would we expect P(A,B)
to be a function of Lambda. We would expect
P(A,B) to be a function of Theta.

This *isn't* an individual measurement
context. Therefore, the variable, L, isn't
part of the joint formulation. (This doesn't
mean that L doesn't exist. :) )

The 'degree' to which the common property
or properties are shared is what's, in effect,
being analyzed by Theta (and being revealed by
violations of Bell inequalities). We're
assuming that it doesn't vary from pair to
pair.

If the polarizer-incident light is the same at
A and B, then coincidental detection should
vary in proportion to cos^2 Theta ... and it
does.

vanesch said:
My explanation (MWI) simply says that the measurement at Bob didn't take place, and only has a meaning when Alice learns about it ; at which point a direct causal influence can be kept local.

The problem with this is that we can ascertain that
Bob's measurement did take place (in a meaningful way
via the permanent, irreversible, time-stamped data
records) before Alice learned about it.

And that's ok because we don't need causal
influences traveling between Alice and Bob to
account for the coincidence curve.
 
  • #108
DrChinese said:
We do understand a lot about entanglement...

There's apparently a lot being done with it. Here's a cool
article in case you might not have seen it.

http://physicsweb.org/articles/news/5/9/12/1

DrChinese said:
... and that is that the entangled particles are in a superposition of states until they are observed.

Right, well that just relates the measurement possibilities wrt
the observational context.

DrChinese said:
During that time, they do not have well defined physical properties - but they nonetheless share the same wavefunction perfectly.

The wavefunction is about the measurement probabilities.
The deep physical properties of the disturbances that are
presumably causing the instrumental changes are not well
known.

DrChinese said:
Further, the assumption you describe has been falsified by experiment IF by physical property you mean properties with definite values (hidden variables).

A photon associated with a detector registration doesn't
exist (except symbolically) until it's produced by the
detector. It is assumed that there is some light associated
with the photon detection, and that this light exists before
the detection event. If the light physically exists prior to
detection , then it has some physical characteristics. But,
the photon detection event doesn't tell us enough about the
light to give a very detailed picture. So, the properties
of the light prior to detection are, in effect, more or less,
hidden. If these properties are varying from emission to
emission (and it's a pretty good bet that they are vis the
individual data streams), then these properties of the light
that is producing the instrumental changes are both
somewhat hidden and variable.

So, I guess something else is meant by hidden variable ...
and I consider that to be a rather confusing way to use the
language. :)

As for the assumption of common properties imparted
at emission. This is not Lambda. It doesn't vary from
pair to pair. It's just the assumption that for any and
all pairs, the light incident on polarizer A is, in effect,
the same as the light incident on polarizer B.

There are no hidden variables *relevant* to coincidental
detection. The relevant variable is Theta. The global
property, the entanglement, of the light incident on
A and B that's being analyzed by Theta is a constant.
At least that's the assumption.
 
  • #109
  • #110
Sherlock said:
You mean? ... P_j is the probability for someone to drive
a Jaguar and *not also* have a Rolex, and P_r is the probability
for someone to have a Rolex and *not also* drive a Jaguar.
P_rj > (P_r)(P_j), so P_r and P_j are not correlated wrt each
other.

No, I mean with P_j, the probability for someone to drive a Jaguar REGARDLESS whether he has a rolex or not !

Just like in the EPR-Bell experiments where P(A) and
P(B) aren't correlated wrt each other. :)

And what is the joint probability for uncorrelated events ? If P1 is the probability to throw heads (usually taken 1/2) of a coin, and P2 is the probability to throw 6 on a dice (usually taken 1/6) what is the JOINT PROBABILITY to throw heads with the coin and a 6 on the dice, assuming that the coin and the dice are giving us uncorrelated probabilities ?
Isn't this P1 x P2 ?

We're analyzing the entanglement. The assumption
is that the entanglement is due to common
properties imparted via common emission event.
In effect, the same light extending from polarizer
to polarizer. We're asking, in effect, to
what degree is it true that the light incident
on the polarizers is the same at A and B for
any set of joint measurements.

You wouldn't write this as,
P(A,B) = (cos^2 |a - L|) (cos^2 |b - L|)

Small correction: this is P(A,B ; L): only for a fixed value of L.

Well, you surely would. L is the polarization angle of the light which is emitted both to A and to B, right ? Now you told me that the probability of being detected by a polarizer under angle a is then (Malus' law) cos^2(a-L). But there is such a detection at A (with incident light under angle L), and there is SUCH AN INDEPENDENT detection at B, this time with angle b.
That's of course the whole point: these detection events are, in a semiclassical model, independent, because there are classically only 2 ways to NOT have statistical independence, which is 1) direct causal influence (which is excluded here because of the spacelike separation) 2) common cause not taken into account. But we DID take the common cause into account with variable L. So FOR A GIVEN VALUE OF L, the events have no EXTRA common cause anymore, and their probabilities are hence independent.

Given our initial assumption, and the
observational context. we wouldn't expect
P(A,B) to be the correlation of P(A) and P(B)
wrt each other. Nor would we expect P(A,B)
to be a function of Lambda. We would expect
P(A,B) to be a function of Theta.

Well, P(A,B) IS of courrse a function of theta, because we don't observe L. So the probabilities given above, depending on L, still have to be weighted over the population of L. But from symmetry it is easy to find out that that population is uniform: p(L) dL = 1/2Pi dL.
After integration of P(A,B ; L) over p(L), you find the OBSERVABLE P(A,B), which is of course NOT equal to P(A) (equal to 1/2) x P(B) (also equal to 1/2). That's because we took into account the "common cause" which was the fact that the polarization L was identical.

This *isn't* an individual measurement
context. Therefore, the variable, L, isn't
part of the joint formulation. (This doesn't
mean that L doesn't exist. :) )

I don't know what you mean. L is determining the probability of detection for an incident beam of polarization L, and, this being the only parameter that determines these probabilities, they are independent at spacelike separated intervals. So of course they are part of it !

The 'degree' to which the common property
or properties are shared is what's, in effect,
being analyzed by Theta (and being revealed by
violations of Bell inequalities). We're
assuming that it doesn't vary from pair to
pair.

I agree with what you say, and I don't vary THETA, I vary L (the incident, common, polarization of the light).

If the polarizer-incident light is the same at
A and B, then coincidental detection should
vary in proportion to cos^2 Theta ... and it
does.

Apart from stating this, how do you obtain it, from the individual detection probabilities ?? You pull this out of nowhere.
You still have to provide me with the probabilities, for an incident beam with polarization L, of:
P(A, ~B ; L) (the probability of A clicking, and B not clicking with incident L)
P(A,B ; L)
P(~A,B ; L)
P(~A,~B ; L)

given that A has its polarizer at angle a and B has its polarizer at angle b, and the probability distribution of L (which should be 1/2Pi given by symmetry, but you are free to specify it).

The problem with this is that we can ascertain that
Bob's measurement did take place (in a meaningful way
via the permanent, irreversible, time-stamped data
records) before Alice learned about it.

Those "irreversible time stamped records" are supposed to be in a superposition of different states (a sheet of paper is in a superposition of having 0 on it, and 1 on it), and Alice chooses which of these branches she will actually observe.
But let us not treat two problems at the same time.

cheers,
patrick.
 
  • #111
vanesch said:
But we DID take the common cause into account with variable L. So FOR A GIVEN VALUE OF L, the events have no EXTRA common cause anymore, and their probabilities are hence independent.

Detection at either end is random and
independent of what happens at the other end.
But you didn't take the common cause(s) of the
correlations into account. Lambda (the *variable*,
from pair to pair, shared properties of the
emitted light) is a factor in determining individual
results, but the combined context isn't analyzing
Lambda.

The combined context is analyzing the, assumed,
*unchanging* relationship between the properties
of the light incident on A and the properties
of the light incident on B for any given
emission/coincidence interval. That is, whatever
the value of Lambda is, it's always the same
at A as it is at B, and vice versa.

The common cause of the shared properties of the
light incident on the polarizers is the emission
event(s) that produced the light.

The common cause of variations in the
rate of coincidental detection is variations
in Theta, the angular difference between the
polarizers.

The variable Lambda determines the rate of
individual detection. Lambda's value has no
effect on the rate of coincidental detection.

P(A) and P(B) are not *correlated* wrt Lambda.

P(A) and P(B) *correlated* wrt Theta.

We're analyzing the shared rotational, and perhaps
other, properties of the light incident on the
polarizers. These properties are assumed to be the
same at A and B for paired (A,B) measurements.
This global parameter (assumed to be produced via
common emission event(s) for photon_1 and photon_2
of any and all pairs) is assumed to be *unchanging*
from pair to pair. (In effect, A and B are, jointly,
always analyzing the same light.)

There's no way to have P(A,B) in the
form of the product of individual probabilities.
P(A) and P(B) *are* causally independent,
but because they're correlated wrt Theta,
then Theta has to be in the formulation
for P(A,B). But there is no Theta (angular
difference between the polarizers) in the
individual contexts, so it obviously
doesn't determine individual results, and
there's obviously no way to express
individual probabilities in terms of Theta.

There *is* a Lambda, in the combined measurement
context. But, it's value is irrelevant wrt
coincidental detection, so it doesn't figure
into the formulation. We're not analyzing
the variable Lambda. We're analyzing the
degree to which the assumed emission-produced
entanglement of the light incident on the
polarizers has been instrumentally produced.

Given the foregoing assumptions, you would
*expect* the rate of coincidental detection to
vary as cos^2 Theta, wouldn't you? I didn't
pull this out of nowhere.:) This is, classically,
the formula that relates the amplitudes of the light
waves that are between the crossed linear polarizers
and their respective detectors (given that
the light incident on (ie., *between*)
the polarizers is the same for any given
coincidence interval.

The entanglement is the common rotational or
other properties imparted via common emission
events -- the commonality of which is assumed
to be constant from pair to pair. It's this
presumably unchanging commonality which is
being analyzed. The only variable in the
joint observational context is Theta.

You can't see the correlations from the
perspective of a combination of the individual
probabilities. But if you envision the process
in terms of variations in Theta and the same
light between the polarizers, then it becomes
clear how rate of coincidental detection must
vary, nonlineary, in proportion to changes in
Theta.

Bell asked if supplementary variable
such as Lambda would be compatible with
QM formulation. The answer is no.
Just not for the reasons that most people
give.

The degree to which Bell inequalities
are violated can tell us something about
the degree to which entanglement has
been instrumentally produced and preserved.
But, it doesn't tell us anything, necessarily,
about exactly where the entanglement is or isn't
produced, or whether nature is local or
nonlocal.
 
  • #112
Sherlock said:
The common cause of the shared properties of the
light incident on the polarizers is the emission
event(s) that produced the light.

The common cause of variations in the
rate of coincidental detection is variations
in Theta, the angular difference between the
polarizers.

How can one polarizer "know" what is the value of theta (and hence the angle of the "other" polarizer, in order to adapt its local detection rate to it ??

The variable Lambda determines the rate of
individual detection. Lambda's value has no
effect on the rate of coincidental detection.

P(A) and P(B) are not *correlated* wrt Lambda.

P(A) and P(B) *correlated* wrt Theta.

Ah, so you mean that for polarized light with a FIXED lambda (say, we use a source which always sends out light with a known polarization direction, for instance because there is a polarizer in the source), the probability of detecting an event at A (that's P(A)) is INDEPENDENT of the angle of polarization of the source ?? So whether the source is at 90 degrees or parallel, that will always result in the same detection rate at A ?
On the other hand, it IS dependent of the angle at B ? That's funny. I thought that light at 90 degrees with respect to a polarizer didn't get through, and light which is parallel got through. But you say that the detection probability is INDEPENDENT of the relative angle between the polarization of the light (Lambda) and the angle of the analyzer at A. It only depends on the angle between the analyzer at A and the angle of the analyser at B. Independent of whether the source is linearly polarized.


There's no way to have P(A,B) in the
form of the product of individual probabilities.
P(A) and P(B) *are* causally independent,
but because they're correlated wrt Theta,
then Theta has to be in the formulation
for P(A,B).

What do you mean by "causally independent" then, if they are not a product ? That's the very definition of statistical independence !
Again, for a source with FIXED, linear polarization under angle Lambda, what do you think that the following probabilities are ?

P(A) (probability of detection at A, with angle a)
P(B) (probability of detection at B, with angle b)
P(A,B) (joint probability of detection at A and B)
P(A, ~B) (joint probability of detection at A and no detection at B).
P(~A,B) (joint probability of detection at B and no detection at A).
P(~A,~B) (joint probability of no detection at A and at B).

Note that, with polarizing beam splitters, P(~A,B) simply means that on the A side, we've got a detection at the OTHER photodetector, and not at the photodetector at angle a. There are two photodetectors on each side, one corresponding to the "correct" angle, and one corresponding to the "perpendicular" angle.

But there is no Theta (angular
difference between the polarizers) in the
individual contexts, so it obviously
doesn't determine individual results, and
there's obviously no way to express
individual probabilities in terms of Theta.

Well, I'm sorry, but P(A) = P(A,B) + P(A,~B) and P(B) = P(A,B) + P(~A,B), so there IS a relationship between P(A), P(B) and P(A,B). By definition, the individual events are statistically independent if P(A,B) = P(A) x P(B). If you can determine (as a function of Theta) what is P(A,B) (and also P(A,~B) etc..), then you have of course fixed P(A) and P(B). So it *does* determine individual results.

Given the foregoing assumptions, you would
*expect* the rate of coincidental detection to
vary as cos^2 Theta, wouldn't you?

No, not at all. Malus' law tells me what I'm supposed to get as a detection probability as a function of THE DIFFERENCE OF THE POLARIZATION ANGLE OF THE LIGHT AND THE DIRECTION OF THE ANALYZER. Malus' law doesn't say anything about two analyzers being correlated or not. So I don't know where you get your cos^2 theta from. Again, do you expect cos^2 theta to be the joint detection probability P(A,B) IRRESPECTIVE of the incident polarization ?

This is, classically,
the formula that relates the amplitudes of the light
waves that are between the crossed linear polarizers
and their respective detectors (given that
the light incident on (ie., *between*)
the polarizers is the same for any given
coincidence interval.

No, it is the formula that gives you the RELATIONSHIP between the light intensity between the two polarizers on one hand, and after the two polarizers on the other (the first polarizer fixes the polarization direction of the light in between, and the second one analyzes this light). But the setup here is different. The light doesn't go through two polarizers in succession. One beam goes to one polarizer, and another beam goes to another.
Imagine one polarizer broken, so that it let's through all light. If we apply you reasoning, we first have a polarizer and next we have a glass plate (broken polarizer). "Malus' law" for this setup is simply 1 (ratio of intensity behind the glass plate to the intensity between glass plate and first polarizer). Do you still maintain that in that case, the joint probability of detection equals 1, irrespectively what is the polarization of the incident light ?
What happens, then, if the incident light is perpendicularly polarized to the one and only polarizer we have ? I'd think that we would have joint probability 0, because the detector behind the polarizer will never click.

cheers,
Patrick.
 
  • #113
vanesch said:
How can one polarizer "know" what is the value of theta (and hence the angle of the "other" polarizer, in order to adapt its local detection rate to it ??

This is the eternal problem of contextuality in QM :tongue2:. The probability law of the 2 random variables is given by (a.A, b.B, |psi>). For every (a,b) we have a couple of different random variables that give the probability law of the QM outcomes.

(Note, I have not read the rest of the post. Sorry if it is completely out of the context).

(just to add more confusion to this thread :rofl: )

Seratend.
 
  • #114
vanesch said:
How can one polarizer "know" what is the value of theta (and hence the angle of the "other" polarizer, in order to adapt its local detection rate to it ??

Well, *one* polarizer can't know the value of Theta.
But, Theta is the observational context that produces the
correlations (predictable *joint* results). So, Theta
is analyzing something which isn't varying randomly. It's
analyzing how *alike* the wavepackets incident on
polarizer_a and polarizer_b are. Theta is analyzing
the degree of sameness of the emitted, paired wavepackets.
Theta is analyzing the entanglement, which is assumed
to not vary from pair to pair. Theta is not analyzing
some/any specific value for Lambda.

If Theta is analyzing the same thing, then if Theta
is 0 we would expect the amplitudes of the wavepackets
transmitted by polarizer_a and polarizer_b to be
the same.

Sherlock said:
The variable Lambda determines the rate of
individual detection. Lambda's value has no
effect on the rate of coincidental detection.

P(A) and P(B) are not *correlated* wrt Lambda.

P(A) and P(B) are *correlated* wrt Theta.

vanesch said:
Ah, so you mean that for polarized light with a FIXED lambda (say, we use a source which always sends out light with a known polarization direction, for instance because there is a polarizer in the source), the probability of detecting an event at A (that's P(A)) is INDEPENDENT of the angle of polarization of the source ?? So whether the source is at 90 degrees or parallel, that will always result in the same detection rate at A?

I mean that in the experiments jointly analyzing
paired wavepackets assumed to be entangled via
emission, the correlation P(A,B;L) doesn't describe
the observational context.

The observational context is the joint settings
of polarizer_a and polarizer_b (Theta) analyzing
the emission-produced entanglement. The entanglement
is not represented by the variable, Lambda.

vanesch said:
What do you mean by "causally independent" then, if they are
not a product ? That's the very definition of statistical
independence!

I mean that P(A) and P(B) are not *causally* related
*to-each-other*. Nor is P(A,B) causally related to
changes in Lambda. P(A,B) is causally related to
changes in Theta, because Theta is analyzing,
simultaneously, the strength of the entanglement
of the wavepackets incident on polarizer_a and
polarizer_b during any given emission/coincidence
interval.

Wrt Theta, the results at A and B, P(A,B), are
not statistically independent.

vanesch said:
... there IS a relationship between P(A), P(B) and P(A,B). By definition, the individual events are statistically independent if P(A,B) = P(A) x P(B). If you can determine (as a function of Theta) what is P(A,B) (and also P(A,~B) etc..), then you have of course fixed P(A) and P(B). So it *does* determine individual results.

I don't think so. Because then you'd be saying that the
*entanglement*, per se, determines individual results. But it
doesn't. The entanglement only (via Theta) determines
joint results. You can't observe the entanglement in the
individual context. You can, sort of, observe Lambda
(the randomly varying wavepacket properties) in the individual
context.

vanesch said:
Malus' law tells me what I'm supposed to get as a detection probability as a function of THE DIFFERENCE OF THE POLARIZATION ANGLE OF THE LIGHT AND THE DIRECTION OF THE ANALYZER. Malus' law doesn't say anything about two analyzers being correlated or not. So I don't know where you get your cos^2 theta from. Again, do you expect cos^2 theta to be the joint detection probability P(A,B) IRRESPECTIVE of the incident polarization?

Cos^2 Theta relates the amplitudes of the wavepackets
produced by the polarizers. These amplitudes (and other,
eg., rotational, properties) are subsets, maybe proper
subsets, of the wavepackets incident on the
polarizers. If a detection is recorded, then the
amplitude of the wavepacket that produced it (the amplitude
of the wavepacket transmitted by the polarizer), whether
the same or different from the emission amplitude and
whether the same or different wrt any other properties
of the emitted wavepacket, can be taken as extending
between the polarizers (ie., contained in the wavepacket
incident on the other polarizer for the same interval).
So, if Theta = 0 then we expect identical results, and
as Theta increases we expect the incidence of indentical
results to decrease as cos^2 Theta.

vanesch said:
No, it is the formula that gives you the RELATIONSHIP between the light intensity between the two polarizers on one hand, and after the two polarizers on the other (the first polarizer fixes the polarization direction of the light in between, and the second one analyzes this light).

It's the formula that gives the relationship between the
amplitude (and therefore the intensity) of the light
produced by the second polarizer wrt the amplitude (intensity)
of the light produced by the first polarizer.

vanesch said:
But the setup here is different.

Yes, somewhat. But, I'm asking you to see the similarities.:)
 
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  • #115
Sherlock said:
Well, *one* polarizer can't know the value of Theta.
But, Theta is the observational context that produces the
correlations (predictable *joint* results). So, Theta
is analyzing something which isn't varying randomly. It's
analyzing how *alike* the wavepackets incident on
polarizer_a and polarizer_b are. Theta is analyzing
the degree of sameness of the emitted, paired wavepackets.
Theta is analyzing the entanglement, which is assumed
to not vary from pair to pair. Theta is not analyzing
some/any specific value for Lambda.

If Theta is analyzing the same thing, then if Theta
is 0 we would expect the amplitudes of the wavepackets
transmitted by polarizer_a and polarizer_b to be
the same.

The problem with this entire argument is that it is exactly what Bell's Theorem was intended to demonstrate could NOT be the case. You cannot advance this argument without addressing Bell first. Period. Vanesch has tried to make this clear. You can say all day long that you MUST be right but that is what makes Bell so special... it forces us to throw out something we would otherwise defend strongly.
 
  • #116
Sherlock said:
So, Theta
is analyzing something which isn't varying randomly. It's
analyzing how *alike* the wavepackets incident on
polarizer_a and polarizer_b are. Theta is analyzing
the degree of sameness of the emitted, paired wavepackets.
Theta is analyzing the entanglement, which is assumed
to not vary from pair to pair. Theta is not analyzing
some/any specific value for Lambda.

If Theta is analyzing the same thing, then if Theta
is 0 we would expect the amplitudes of the wavepackets
transmitted by polarizer_a and polarizer_b to be
the same.

I agree with you about 2 points:
1) P(A,B) will be a function of theta. But it will of course also be a function of the polarization of the incident light.
2) if theta = 0, then the amplitudes of the wavepackets transmitted by polarizer_a and polarizer_b are to be the same.

But remember that that doesn't mean that P(A,B) is equal to 1. Let us suppose for a moment that a = b. If the incident light is perpendicular to a and b, then P(A,B) = 0. If the incident light is parallel to a and b, then P(A,B) = 1. I could think you agree with that ? So this proves already that P(A,B), in the case of a = b, is not only a function of theta (= 0), because we obtain two different values for the same theta !

You still didn't give me P(A,B ; a, b, L) and the complementary functions P(~A,B ; a,b,L) etc... If you think that L doesn't play a role, then just write a function that doesn't depend on L.

cheers,
Patrick.
 
  • #117
Sherlock said:
Well, *one* polarizer can't know the value of Theta.
But, Theta is the observational context that produces the
correlations (predictable *joint* results). So, Theta
is analyzing something which isn't varying randomly. It's
analyzing how *alike* the wavepackets incident on
polarizer_a and polarizer_b are. Theta is analyzing
the degree of sameness of the emitted, paired wavepackets.
Theta is analyzing the entanglement, which is assumed
to not vary from pair to pair. Theta is not analyzing
some/any specific value for Lambda.

If Theta is analyzing the same thing, then if Theta
is 0 we would expect the amplitudes of the wavepackets
transmitted by polarizer_a and polarizer_b to be
the same.

DrChinese said:
The problem with this entire argument is that it is exactly what Bell's Theorem was intended to demonstrate could NOT be the case. You cannot advance this argument without addressing Bell first. Period. Vanesch has tried to make this clear. You can say all day long that you MUST be right but that is what makes Bell so special... it forces us to throw out something we would otherwise defend strongly.

I'm not saying that I must be right. I'm just presenting a way of
looking at these sorts of experiments that seems to me to make
sense.

Bell showed that the correlations can't be due to Lambda -- unless
some sort of superluminal causal influence or signal is involved.
I agree with that. The correlations aren't due to Lambda.

The correlations are due to the analysis of a global property
(the entanglement of the light incident on the polarizers) that
is revealed in the context of joint polarizer settings (Theta),
but not in the context of individual measurement.

The entanglement isn't a variable. The entanglement isn't
represented by Lambda. The only thing varying in
the joint context that is relevant to coincidental detection
is Theta.

Bell didn't deal with that, and so violations of Bell inequalities
don't contradict the idea that the entanglement is produced
at emission, and therefore coincidental detection varies
nonlinearly as a function of this (presumed) unchanging
global property of the incident light (the entanglement)
being analyzed simultaneously by crossed linear polarizers.

Now, if anyone has any specific objection to the view
I've presented, other than to offer a reiteration of why
Lambda can't be responsible for the correlations (which I
agree with), then I'm glad to hear it.

I'm quite familiar with Bell's analysis. One day the thought
struck me that Bell's Theorem isn't really dealing with
what is happening in the experiments. It isn't dealing
with the actual observational context. We're not analyzing
a variable (Lambda), we're analyzing a constant (the
entanglement). So, of course, the correct correlation
function can't be generated via individual contexts
wrt Lambda.
 
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  • #118
vanesch said:
I agree with you about 2 points:
1) P(A,B) will be a function of theta. But it will of course also be a function of the polarization of the incident light.

It's only a function of Theta. And, I'll grant you that that *is*
the hardest thing to envision. But, keep in mind that it isn't
Lambda that's being analyzed. Whatever amplitude was transmitted
by one polarizer to produce a detection, it's, a subset of the
light that's incident on the other polarizer for that interval
(via the assumption of emission entanglement).

vanesch said:
2) if theta = 0, then the amplitudes of the wavepackets transmitted by polarizer_a and polarizer_b are to be the same.

But remember that that doesn't mean that P(A,B) is equal to 1.

P(A,B) is the probability of coincidental detection, ++ or --. So,
if Theta = 0 then P(A,B) = 1. In the actual experiments, I don't
think there's any way to count coincidental nondetections, since
the coincidence circuitry is only activated upon detection at
either A or B.

vanesch said:
Let us suppose for a moment that a = b. If the incident light is perpendicular to a and b, then P(A,B) = 0. If the incident light is parallel to a and b, then P(A,B) = 1. I could think you agree with that ? So this proves already that P(A,B), in the case of a = b, is not only a function of theta (= 0), because we obtain two different values for the same theta!

Another nice demonstration of why trying to explain the
correlations in terms of assumed values for Lambda is
not the right approach. :)

vanesch said:
You still didn't give me P(A,B ; a, b, L) and the complementary functions P(~A,B ; a,b,L) etc... If you think that L doesn't play a role, then just write a function that doesn't depend on L.

P(A,B) = cos^2 Theta. :)

This is an empirical law that applies to setups which I
think are quite similar to the archetypal EPR-Bell tests
(eg. Aspect et al.). Afaik, there's no way to get that
function using Lambda.

I could be quite wrong in my analogizing, but so far I
don't think so. In my perusal of several books and
a few dozen papers dealing with Bell stuff, I haven't
seen this line of reasoning used. But you probably
have read more articles than I. Anyway, if it is
a novel approach, then maybe you can develop
it into a paper. Or, maybe you'll demolish the
idea in your next message. One never knows. :)
 
  • #119
Sherlock said:
P(A,B) is the probability of coincidental detection, ++ or --.

No, a priori P(A,B) is the probability of detector A and detector B clicking, in an arbitrary interval of, say, 10 ns.
P(A) is the probability of detector A clicking in an arbitrary interval of 10 ns and P(B) is the probability of detector B clicking in an arbitrary interval of 10 ns.

However, the quantum probabilities are renormalized on 1-photon events, but of course this is not possible in a semiclassical model, which will introduce an overall "attenuation": most of the time, A doesn't click, and B doesn't click.

I would like to point out that we can normalize (in quantum theory) quite easily onto the number of photon events: indeed, we do not use absorbing polarizers, but polarizing beam splitters, with 2 detectors. The transmitted beam is the same as of an absorbing polarizer, but the complementary part which is absorbed in an absorbing polarizer is now sent into the reflected beam, so that there is conservation of intensity. We will call that event An.
If the detectors are perfectly efficient, then always exactly one detector (A or An) triggers ; otherwise sometimes they do not. But they NEVER trigger together (this exclusiveness cannot be explained classically btw).
So we can normalize on a click in ONE OF BOTH detectors. When we do so, P(A) + P(An) = 1, so we can take An to be equivalent to ~A (thanks to the exclusiveness of A and An).
Semiclassically you can then do the same: P(A,B) is then defined as the probability that A and B click together, when at A, one of both detectors (A or An) triggers. Mind you that this is NOT the same than P(B | A). Indeed, B can click when An clicks.
The only serious problem is that semiclassically, there is no way to stop A and An to click BOTH. But this is not empirically observed (Thorn's experiment!) and moreover not allowed for by QED. So use as a normalization P(A or An).

When the light is polarized, and is perpendicular to a and b (theta = 0), then it is ALWAYS An and Bn that trigger, never A or B. So this leads to P(A,B) = 0. When the light is polarized and parallel to a and b, then it is always A and B that trigger, never An or Bn, and we have P(A,B) = 1.

So,
if Theta = 0 then P(A,B) = 1. In the actual experiments, I don't
think there's any way to count coincidental nondetections, since
the coincidence circuitry is only activated upon detection at
either A or B.

There is, using a polarizing beam splitter and two detectors on each side, as was first done by Aspect.

P(A,B) = cos^2 Theta. :)

Clearly this is wrong when the incident light is perpendicular to a and b, in which case P(A,B) = 0. But you were not using the right P(A,B), which is the probability for A and B to click together when A or An click. (or when B or Bn click, which is the same in the case of perfect detectors - which we don't have but correct for finite efficiency).

This is an empirical law that applies to setups which I
think are quite similar to the archetypal EPR-Bell tests
(eg. Aspect et al.). Afaik, there's no way to get that
function using Lambda.

Indeed, there is no way to get that function using lambda, and that's exactly the content of Bell's theorem !

cheers,
Patrick.
 
  • #120
Sherlock said:
I'm not saying that I must be right. I'm just presenting a way of looking at these sorts of experiments that seems to me to make
sense.

Bell showed that the correlations can't be due to Lambda -- unless
some sort of superluminal causal influence or signal is involved.
I agree with that. The correlations aren't due to Lambda.

The correlations are due to the analysis of a global property
(the entanglement of the light incident on the polarizers) that
is revealed in the context of joint polarizer settings (Theta),
but not in the context of individual measurement.

The entanglement isn't a variable. The entanglement isn't
represented by Lambda. The only thing varying in
the joint context that is relevant to coincidental detection
is Theta.

Bell didn't deal with that, and so violations of Bell inequalities
don't contradict the idea that the entanglement is produced
at emission, and therefore coincidental detection varies
nonlinearly as a function of this (presumed) unchanging
global property of the incident light (the entanglement)
being analyzed simultaneously by crossed linear polarizers.

Now, if anyone has any specific objection to the view
I've presented, other than to offer a reiteration of why
Lambda can't be responsible for the correlations (which I
agree with), then I'm glad to hear it.

I have a specific objection: your idea that the incident light produces a "presumed" function Theta which has a) hidden variables, but no Lambda; and b) the correlations still change according to distant settings prepared while the photons are in flight.

You don't need Lambda anyway to get Bell's Theorem. All you need to believe is that the wave function had a definite value for ANY possible polarizer setting at one of the detectors independent of the setting at the other. That is at the base of your presumption no matter how you try to describe it. Specifically, that results for polarizer settings A, B AND C could all exist simultaneously. If you say there are only A and B, you are describing the QM view.

Vanesch has called for you to present some details of your Theta. The burden is now on you to present something other than a few words if you want to make a convincing argument. It may make "sense" to you, but it doesn't make sense to me. You may as well just say that you assume you are right, and are leaving the details of your argument to someone else.
 
  • #121
Sherlock said:
I'm quite familiar with Bell's analysis. One day the thought
struck me that Bell's Theorem isn't really dealing with
what is happening in the experiments. It isn't dealing
with the actual observational context. We're not analyzing
a variable (Lambda), we're analyzing a constant (the
entanglement). So, of course, the correct correlation
function can't be generated via individual contexts
wrt Lambda.

What do you want to proove? Bell theorem assumes non contextual random variables.
Contextual random variables (as well as contextual sample space) are known to be able to reflect quantum probabilites, there are plenty of documents concerning this subject in arxiv (for example quant-ph/0301027). There is nothing new about that.

Seratend.
 
  • #122
DrChinese said:
You don't need Lambda anyway to get Bell's Theorem.

This is correct, but as Sherlock talked about a semiclassical model, I was presuming Maxwellian light ; then the only degree of freedom left is Lambda of course. But you can feel free to include into lambda all hidden or non-hidden parameters that come from the source.

All you need to believe is that the wave function had a definite value for ANY possible polarizer setting at one of the detectors independent of the setting at the other. That is at the base of your presumption no matter how you try to describe it. Specifically, that results for polarizer settings A, B AND C could all exist simultaneously. If you say there are only A and B, you are describing the QM view.

Indeed, the actual factorisation P(A,B ; L) = P(A ; L) x P(B ; L) is not even necessary (but helpful when we DO have a model that gives us P(A ; L) such as is the case in the semiclassical treatment). The only thing it assures, as you point out, is that, given a statistical distribution p(L), P(A,B), P(A,C) and P(B,C) have simultaneous meaning within a Kolmogorov probability universe ; or said differently, that they can be derived from a hypothetical P(A,B,C) even if that P(A,B,C) is not, even in principle, ever measurable.
It is in fact sufficient to postulate the existence of a P(A,B,C) ; but that would run into the objection of being non-physical given that we cannot measure it ; even though this is a weaker hypothesis than the Bell factorization hypothesis. But from the Bell factorization hypothesis we can easily construct the "forbidden" P(A,B,C) by just integrating
P(A ; L) x P(B ; L) x P(C ; L) over p(L)
Indeed, summing P(A,B,C) over C and ~C gives us then P(A,B) ; summing over A and ~A gives us P(B,C) and summing over B and ~B gives us P(A,C) ; simply by bringing the sum inside the integral over p(L).
As such, the (stronger) factorization hypothesis gives us a natural framework to define a hypothetical P(A,B,C) ; and once such a P(A,B,C) exists from which we can derive the P(A,B), P(A,C) and P(B,C), Bell's inequalities are satisfied (and hence incompatible with QM).

cheers,
Patrick
 
  • #123
DrChinese said:
I have a specific objection: your idea that the incident light produces a "presumed" function Theta which has a) hidden variables, but no Lambda; and b) the correlations still change according to distant settings prepared while the photons are in flight.

Theta is the angular difference between the polarizers associated
with a given pair. I don't know where you got the idea that the
incident light has anything to do with Theta.

And, of course the value of the correlation function changes if
you change Theta while the emitted light associated with
a pair of photons is still incident on one or both of the polarizers.
But, there is always one and only one Theta associated with
a given coincidence interval.

DrChinese said:
You don't need Lambda anyway to get Bell's Theorem. All you need to believe is that the wave function had a definite value for ANY possible polarizer setting at one of the detectors independent of the setting at the other. That is at the base of your presumption no matter how you try to describe it. Specifically, that results for polarizer settings A, B AND C could all exist simultaneously. If you say there are only A and B, you are describing the QM view.

Vanesch has called for you to present some details of your Theta. The burden is now on you to present something other than a few words if you want to make a convincing argument. It may make "sense" to you, but it doesn't make sense to me. You may as well just say that you assume you are right, and are leaving the details of your argument to someone else.

No offense please, but I think maybe you haven't read what
I've written. Otherwise you wouldn't be asking for details of Theta.
 
  • #124
seratend said:
Bell theorem assumes non contextual random variables.

That's exactly why Bell's theorem is irrelevant wrt questions of
'locality' and 'realism'.

seratend said:
Contextual random variables (as well as contextual sample space) are known to be able to reflect quantum probabilites, there are plenty of documents concerning this subject in arxiv (for example quant-ph/0301027). There is nothing new about that.
Seratend.

In the observational context (that's described by cos^2 Theta),
Theta isn't analyzing a variable, random or otherwise.
Theta is analyzing the entanglement, which is assumed to
be produced via emission, and to not vary from pair to pair.

I'll check out the reference you provided. Thanks.
 
  • #125
vanesch said:
... as Sherlock talked about a semiclassical model, I was presuming Maxwellian light ; then the only degree of freedom left is Lambda of course. But you can feel free to include into lambda all hidden or non-hidden parameters that come from the source.

I'm not assuming anything about the details of the incident light.
Except that it's entangled at emission, which means that whatever
is incident on the polarizers is the same at both ends.

vanesch said:
Indeed, the actual factorisation P(A,B ; L) = P(A ; L) x P(B ; L) is not even necessary (but helpful when we DO have a model that gives us P(A ; L) such as is the case in the semiclassical treatment). The only thing it assures, as you point out, is that, given a statistical distribution p(L), P(A,B), P(A,C) and P(B,C) have simultaneous meaning within a Kolmogorov probability universe ; or said differently, that they can be derived from a hypothetical P(A,B,C) even if that P(A,B,C) is not, even in principle, ever measurable.
It is in fact sufficient to postulate the existence of a P(A,B,C) ; but that would run into the objection of being non-physical given that we cannot measure it ; even though this is a weaker hypothesis than the Bell factorization hypothesis. But from the Bell factorization hypothesis we can easily construct the "forbidden" P(A,B,C) by just integrating
P(A ; L) x P(B ; L) x P(C ; L) over p(L)
Indeed, summing P(A,B,C) over C and ~C gives us then P(A,B) ; summing over A and ~A gives us P(B,C) and summing over B and ~B gives us P(A,C) ; simply by bringing the sum inside the integral over p(L).
As such, the (stronger) factorization hypothesis gives us a natural framework to define a hypothetical P(A,B,C) ; and once such a P(A,B,C) exists from which we can derive the P(A,B), P(A,C) and P(B,C), Bell's inequalities are satisfied (and hence incompatible with QM).

As you show, if you omit Lambda from the formulation, then
you get a 'nonphysical' Bell's theorem. This is the generality of
the relationship that the theorem describes. It's just arithmetic.

However, including Lambda makes it irrelevant wrt the observational
context that we're considering in the sense that it is supposedly telling
us that nature is nonlocal and that hidden variables don't exist. But, if
Lambda isn't a factor in determining rate of coincidental detection,
(which Bell and you and many others have shown)
then Bell's theorem isn't telling us that nature is nonlocal and
hidden variables don't exist. What it does give, via the degree of
violation of Bell inequalties, is sort of a rough quantitative measure
of the strength of the entanglement.
 
  • #126
Sherlock said:
1. Theta is the angular difference between the polarizers associated with a given pair. I don't know where you got the idea that the
incident light has anything to do with Theta.

2. And, of course the value of the correlation function changes if
you change Theta while the emitted light associated with
a pair of photons is still incident on one or both of the polarizers.
But, there is always one and only one Theta associated with
a given coincidence interval.

1. You said:

Sherlock said:
The correlations are due to the analysis of a global property
(the entanglement of the light incident on the polarizers) that
is revealed in the context of joint polarizer settings (Theta),
but not in the context of individual measurement.

2. Your position, as stated here, is the QM position. It is not the local realistic position you are trying to defend. It is QM that states that Theta is fundamental in the sense that the act of observation creates the reality. Local realism states that there are hidden local variables.

No offense, but your words are those of someone who ignores Bell completely. The point is simple: you postulate that local reality is maintained but refuse to accept any physical meaning to that statement. Bell provides such meaning and it is generally accepted. We all agree that theta is an observable in the sense you describe. But QM says that there is no underlying reality to individual elements of reality outside of the context of a measurement, an idea you appear to deny.
 
  • #127
Sherlock said:
It's just arithmetic.

Yes, but it is the arithmetic used in all of science, especially medicine and sociology. It is the amazing fact that QM does NOT follow this arithmetic that is profoundly surprising, and I don't see how you can miss that point !

You are correct of course to state that quantum theory, as an epistemological stochastic theory, can just as well posit correlations as individual probabilities, without their being a) a direct causal influence or b) common cause: probabilities fall out of the sky, and just as well joint probabilities. There is no such thing as causal relation, common cause or whatever. Just probabilities. But that only goes as far as one attaches only an epistemological value to quantum predictions.
If one tries to give an ontological meaning to the quantum formalism, or even to another theory that has equivalent statistical predictions, and one assumes that, ONCE ALL COMMON CAUSES ARE TAKEN INTO ACCOUNT, PROBABILITIES AT SPACE-LIKE SEPARATED EVENTS MUST BE STATISTICALLY INDEPENDENT, (these are the assumptions of Bell's theorem) then this doesn't work. And the above assumption is part of all of classical statistical physics, so no semiclassical model can produce the probabilities generated by entangled quantum states.

However, including Lambda makes it irrelevant wrt the observational
context that we're considering in the sense that it is supposedly telling
us that nature is nonlocal and that hidden variables don't exist.

Lambda, as polarization direction of classical light, is normally what should locally describe completely what happens to the light (the intensity getting through the polarizer) ; and the above assumption, namely the random clicking of the detector as a function of the transmitted intensity, should then be a statistically independent variable of any OTHER such detection process. Only the intensity counts to give us the probability of clicking per unit of time, and this should be an independent Poisson process of any other clicking.
This is clearly NOT what quantum theory predicts.

Let me try to give you one more analogy. Assume that balls of different colors, namely blue, red or green, can be put into a bag, and transported to Alice and Bob. It is such that each time a red ball is put in Alice's bag, then also a red ball is put into Bob's bag and so on. So they are always identical colors (that's the "common cause"). Now assume that on Alice's side, someone takes the ball and throws a dice, with outcome Da, which can be 1,2,3,4,5 or 6.
Alice chooses the order of the 3 colors, let us say, red - green - blue.
Now, if the ball is red (no matter what is Da), or if the ball is green and Da>3 or if the ball is blue and Da>4, then he "clicks" to Alice ; the same thing is done at Bob's side after Bob has choosen his order of colors.
Clearly, in the case that Alice and Bob choose the same order of colors, red -green - blue, P(Alice click) = p(red) + 1/2 p(green) + 1/3 p(blue), the same for Bob, and the probability for P(Alice AND Bob click) = p(red) + 1/4 p(green) + 1/9 p(blue). So we don't have that
P(Alice AND Bob click) = P(Alice click) x P(Bob click)

However, if we take into account the common cause (the color of the ball) then we do have:
for red: P(Alice click ; red) = 1 ; P (Bob click ; red) = 1 ; P(Alice+Bob click ; red) = 1

for green: 1/2 ; 1/2 and 1/4 respectively

for blue: 1/3, 1/3 and 1/9 respectively.

The reason is that, after having taken all COMMON CAUSES into account, the fundamentally stochastic elements (the dice at each place) are supposed to be statistically independent. This is the fundamental hypothesis in Bell's theorem, and in fact in all statistical analysis ever done to find causal (or common origin) relations.


if
Lambda isn't a factor in determining rate of coincidental detection,
(which Bell and you and many others have shown)
then Bell's theorem isn't telling us that nature is nonlocal and
hidden variables don't exist. What it does give, via the degree of
violation of Bell inequalties, is sort of a rough quantitative measure
of the strength of the entanglement.

But I tried to illustrate that Lambda IS such a factor, in the case the source is polarised: in the case that the source (lambda) is perpendicular to both a and b (theta = 0) the rate of coincidental detection is ZERO !
While it isn't when the source is parallel to both a and b.

cheers,
Patrick.
 
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  • #128
vanesch said:
... a priori P(A,B) is the probability of detector A and detector B clicking, in an arbitrary interval of, say, 10 ns.
P(A) is the probability of detector A clicking in an arbitrary interval of 10 ns and P(B) is the probability of detector B clicking in an arbitrary interval of 10 ns.

Wrt P(A,B), Theta is analyzing a global constant
which is not revealed (ie., is not relevant to P(A) or
P(B)) in the individual context.

And, wrt P(A) or P(B) the individual polarizers are analyzing
a variable which is not relevant to P(A,B), which variable if you globalize it to account for P(A,B) gives an incorrect description.

vanesch said:
When the light is polarized, and is perpendicular to a and b (theta = 0), then it is ALWAYS An and Bn that trigger, never A or B. So this leads to P(A,B) = 0. When the light is polarized and parallel to a and b, then it is always A and B that trigger, never An or Bn, and we have P(A,B) = 1.

You're confusing the issue. Lambda is irrelevant.

If An and Bn trigger in the same interval, then that is a
coincidental detection at An and Bn.

Coincidental detection at An and Bn is the
same as coincidental nondetection at A and B.

We're dealing with the probability of coincidental detection,
which means getting the same detection attributes at A and
B for a given interval.
The probability of coincidental detection when Theta = 0
is 1.

The incident light can be polarized any way you like. As
long as the two polarizers are analyzing the same thing,
and are aligned, then you get coincidental detection.

vanesch said:
Indeed, there is no way to get that function using lambda, and that's exactly the content of Bell's theorem !

And that tells you ... what? :)

There are at least three possible physical reasons why Lambda
doesn't account for P(A,B).

(1) nature is nonlocal

(2) hidden variables don't exist

(3) Lambda isn't what Theta is measuring

I've simply chosen (3) as my starting point
in attempting to understand some of this stuff. It seems
like the most parsimonious assumption to make at this time.
Formulations of P(A,B) using Lambda simply don't describe
the 'reality' of the observational context.

All of your analysis, and Bell's analysis, is consistent
with (3) -- which option is also consistent
with standard physics.

The second option (2) is inconsistent with individual
results.

The first option (1) is just speculation, the
foundation of which is a misinterpretation of the
meaning of Bell's work and the qm formulation.
 
  • #129
DrChinese said:
Your position, as stated here, is the QM position. It is not the local realistic position you are trying to defend.

In a sense that's right. I'm understanding the QM prediction
by seeing that the entanglement, not Lambda, is the relevant
emission-produced global parameter of the incident light.

And this is only revealed in the observational context defined
by Theta.

Everything is quite locally explained in this view, and
there is a global parameter of the incident light which
exists prior to polarization at the polarizers and detection
at the detectors.

So, you could call this a local realist interpretation of
the qm formalism. At least for the types of experiments
we're considering.

DrChinese said:
It is QM that states that Theta is fundamental in the sense that the act of observation creates the reality. Local realism states that there are hidden local variables.

Theta isn't fundamental. It's just crossed linear polarizers.
The entanglement is fundamental. Local realism says that
the entanglement (remember that it's assumed to be constant,
never varying from pair to pair like Lambda does) is produced
at emission.

DrChinese said:
No offense, but your words are those of someone who ignores Bell completely. The point is simple: you postulate that local reality is maintained but refuse to accept any physical meaning to that statement.

No offense taken. :) But, if read my posts carefully, then you'll
see how local reality is maintained in the view I've been
presenting, and why Bell's analysis is irrelevant to the question
of local reality.

DrChinese said:
Bell provides such meaning and it is generally accepted. We all agree that theta is an observable in the sense you describe.

Bell provided a formulation in terms of Lambda, an emission-produced,
*variable* global parameter of the incident light. He showed that
this formulation is incompatible with qm predictions and experiments
have shown that his formulation is incompatible with reality.

Now, one can just stop there and say that Bell has shown that
there's no local reality. And, that's what it seems that most
people do. But, that is a wrong conclusion because there still
exists the possibility that Bell's formulation is simply irrelevant
to the observational context -- which is the view I currently take.

I've explained that the correlations aren't caused by a *variable* global parameter of the incident light, but rather are produced by a *constant*
global parameter of the incident light when viewed in the context
of the variable Theta (the angular difference between the polarizers).

DrChinese said:
But QM says that there is no underlying reality to individual elements of reality outside of the context of a measurement, an idea you appear to deny.

Yes, I would deny the idea that there's no reality underlying
measurement results. Quantum theory was developed
with the idea that a qualitative understanding of the reality
underlying measurement results was not possible. It's not
denying the existence of an underlying reality. That would
be silly. Obviously the instruments are measuring *something*. :)
 
  • #130
Sherlock said:
In a sense that's right. I'm understanding the QM prediction by seeing that the entanglement, not Lambda, is the relevant
emission-produced global parameter of the incident light.

And this is only revealed in the observational context defined
by Theta.

Everything is quite locally explained in this view, and
there is a global parameter of the incident light which
exists prior to polarization at the polarizers and detection
at the detectors.

So, you could call this a local realist interpretation of
the qm formalism. At least for the types of experiments
we're considering.

...

Yes, I would deny the idea that there's no reality underlying
measurement results. Quantum theory was developed
with the idea that a qualitative understanding of the reality
underlying measurement results was not possible. It's not
denying the existence of an underlying reality. That would
be silly. Obviously the instruments are measuring *something*. :)

OK, I am trying to follow your reasoning - so maybe the above gets us closer.

1. What, then, is a "global parameter of the incident light" ? If it is the entangled wavefunction, then this is a description that exactly matches QM. To use your words, this exists prior to the photons arriving at the polarizers.

2. Clearly, you get different results when you use different Thetas. But since Theta is determined AFTER emission and while the photons are separated, how is this a local effect?

3. And finally: why are you convinced that Bell does not apply, if in fact you say that local hidden variables exist? You say that "Bell's formulation is simply irrelevant to the observational context" because the global parameter is "constant" rather than "variable" (?). But that wouldn't make any difference to Bell's formulation anyway.
 
  • #131
Sherlock said:
Wrt P(A,B), Theta is analyzing a global constant
which is not revealed (ie., is not relevant to P(A) or
P(B)) in the individual context.

I don't know what these words are supposed to mean. Do you mean that the outcomes at A and B, when "looking at the global constant" are somehow different than those same outcomes, when we "look at them in the individual context" ?

And, wrt P(A) or P(B) the individual polarizers are analyzing
a variable which is not relevant to P(A,B), which variable if you globalize it to account for P(A,B) gives an incorrect description.

But from P(A,B) and P(A,~B) you can calculate P(A) of course: that's basic probability theory.


If An and Bn trigger in the same interval, then that is a
coincidental detection at An and Bn.

Coincidental detection at An and Bn is the
same as coincidental nondetection at A and B.

I'm talking about the probability P(A,B): the probability of joint detection in directions a and b. Whether or not there has been a joint detection at An and Bn is irrelevant, because it doesn't contribute to P(A,B). So again, what is your proposal for P(A,B) (the joint probability of a detection at A and B (and not An or Bn)) ; you claim this to be independent of the incident polarization, which means I can change it the way I want (random distribution, or a fixed, chosen direction). I'm telling you that in one case we have P(A,B) = 1 (high rate of coincident clicks between A and B) and in another case we have P(A,B) = 0 (rate of coincident clicks 0), for the same theta. So P(A,B) cannot be independent of that polarization direction, no ?

We're dealing with the probability of coincidental detection,
which means getting the same detection attributes at A and
B for a given interval.
The probability of coincidental detection when Theta = 0
is 1.

It is clearly 0 in the case that incident light is perpendicular to both a and b because no light gets through on both sides ! Again, P(A,B) is the counting rate for A and B to click together. If A and B never click, their coincident counting rate is 0, no ?

cheers,
Patrick.
 
  • #132
vanesch said:
I don't know what these words are supposed to mean. Do you mean that the outcomes at A and B, when "looking at the global constant" are somehow different than those same outcomes, when we "look at them in the individual context" ?

Theta analyzes the *relationship* between the light incident
on the polarizers regardless of the specific polarization of
the incident light.

An individual polarizer analyzes the specific polarization of
the incident light.

The outcomes at A are random.
The outcomes at B are random.
The combined outcomes at A and B are random
unless you correlate them wrt Theta.
Why? Because Theta is analyzing
the entanglement, which is something
different than what either polarizer by
itself is analyzing.

vanesch said:
I'm talking about the probability P(A,B): the probability of joint detection in directions a and b. Whether or not there has been a joint detection at An and Bn is irrelevant, because it doesn't contribute to P(A,B). So again, what is your proposal for P(A,B) (the joint probability of a detection at A and B (and not An or Bn))

You're right, it's .5 cos^2 Theta.

vanesch said:
; you claim this to be independent of the incident polarization, which means I can change it the way I want (random distribution, or a fixed, chosen direction). I'm telling you that in one case we have P(A,B) = 1 (high rate of coincident clicks between A and B) and in another case we have P(A,B) = 0 (rate of coincident clicks 0), for the same theta. So P(A,B) cannot be independent of that polarization direction, no ?

The coincidence rate at A and B with Theta = 0 is .5
no matter what the incident, common polarization is.

vanesch said:
It is clearly 0 in the case that incident light is perpendicular to both a and b because no light gets through on both sides !

We don't know what the incident polarization is. Presumably,
during any run, with Theta = any angle, the incident polarization is
cycling through the entire range. So, the rate of coincidental
detection would seem to be independent of the direction of
the incident polarization.

With Theta = 0 then the coincidental detection rate should
be the same as the individual rate which is .5, and
I think that's about what's gotten experimentally.
 
  • #133
DrChinese said:
OK, I am trying to follow your reasoning - so maybe the above gets us closer.

1. What, then, is a "global parameter of the incident light" ? If it is the entangled wavefunction, then this is a description that exactly matches QM. To use your words, this exists prior to the photons arriving at the polarizers.

The global parameter of the incident light is that the light incident
on polarizer_a is the same as the light incident on polarizer_b
during a given coincidence interval.
This includes being in phase, which is important wrt how the
amplitudes of the incident waves are (jointly) altered by the
polarizers, and therefore how the amplitudes of the waves
transmitted by the polarizers during a coincidence interval
are related for that interval.

This global parameter is a constant. It's what all variations
of Lambda have in common. Can we just call it Lambda?
I don't know.

DrChinese said:
2. Clearly, you get different results when you use different Thetas.

The predictability of which implies that the variable
Theta is analyzing something that isn't changing randomly.
But, Lambda is changing randomly -- so that presents
a difficulty in how to talk about what it is that Theta
is analyzing.

Note that the rate of coincidental detection is
*only* due to changes in Theta.

DrChinese said:
But since Theta is determined AFTER emission and while the photons are separated, how is this a local effect?

One Theta (the angular difference between the settings
of two spacelike separated polarizers) is analyzing the
relationship between the light incident on the polarizers
during a given coincidence interval.

Theta is the common (global) variable cause of the predictably
variable joint results.

Individual results are random sequences.

Combine these random sequences wrt coincidence
intervals and they're still random sequences.

Correlate the combined results wrt Theta,
and wrt a given Theta you can expect
to get n coincidental detections per unit time
(with n varying as .5 cos^2 Theta).

DrChinese said:
3. And finally: why are you convinced that Bell does not apply, if in fact you say that local hidden variables exist?

I'm not necessarily *convinced* -- it's just one
approach. And, I'm only exploring the idea that
Bell doesn't apply to questions of locality and
realism.

No matter what is eventually learned, Bell's
analysis is extremely important.

I have the idea that local hidden variables exist
because it seems most parsimonious to assume
that the random variability of individual
results is coming from the emission events.
But, as you've noted, for all anyone knows, it
could be produced at/in the polarizer, or at/in the
detector, or between the emitter and the polarizer,
or between the polarizer and the detector, or ...

However, the setups and instruments are calibrated
very carefully, so the likelihood of something
other than the emission events being the cause
seems rather small.

DrChinese said:
You say that "Bell's formulation is simply irrelevant to the observational context" because the global parameter is "constant"
rather than "variable" (?).

The *relevant* global parameter (of the incident light)
for the *predictable* (that is, correlated wrt Theta)
joint results can't be varying randomly -- because
the number of coincidental detections per unit time
wrt a given Theta isn't random.

Bell's program was to see if the globalization of
an emission-produced variable parameter (that, if known,
would make individual results predictable) could duplicate
the qm corrlation function for singlet-type setups.

The problem is that predictable joint results
are due to the global variable Theta and a
constant global parameter of the light.

DrChinese said:
But that wouldn't make any difference
to Bell's formulation anyway.

It would make a difference in how experimental
violations of Bell inequalities are interpreted
(that is, it would make a difference wrt the
relevancy of Bell's theorem to questions of
local realism).
 
Last edited:
  • #134
Sherlock said:
We don't know what the incident polarization is. Presumably,
during any run, with Theta = any angle, the incident polarization is
cycling through the entire range. So, the rate of coincidental
detection would seem to be independent of the direction of
the incident polarization.

In the case of the entanglement |0>|0> + |90>|90> yes, but your reasoning should also hold when I use a source with a SPECIFIC, fixed polarization (for instance when there are polarizers at each output of the source!). Quantum mechanically, this corresponds to a pure state, |0>|0> for instance.
As you claim that P(A,B) does not depend on the specific polarization direction in the case |0>|0> + |90>|90>, it should also not depend on it in the case |0>|0>. Now that's where I present you with the problem that in the case I have |0>|0> (and imagine that a and b are both 0, with theta 0) I will have P(A,B) = 1 (namely EVERYTHING gets through, on both sides), and if I now change a and b to 90 degrees, keeping |0> |0>, NOTHING gets through, and P(A,B) = 0.
So clearly P(A,B) cannot be only a function of theta, but must depend also on the angle between the polarization direction of the source and a and b, in this case. But according to your claims, it is always the same value, no matter what the incident polarization, as long as theta is a constant.

cheers,
Patrick.
 
  • #135
Sherlock said:
1. The global parameter of the incident light is that the light incident on polarizer_a is the same as the light incident on polarizer_b
during a given coincidence interval.
This includes being in phase, which is important wrt how the
amplitudes of the incident waves are (jointly) altered by the
polarizers, and therefore how the amplitudes of the waves
transmitted by the polarizers during a coincidence interval
are related for that interval.

2. This global parameter is a constant. It's what all variations
of Lambda have in common. Can we just call it Lambda?
I don't know.

The predictability of which implies that the variable
Theta is analyzing something that isn't changing randomly.
But, Lambda is changing randomly -- so that presents
a difficulty in how to talk about what it is that Theta
is analyzing.

3. Note that the rate of coincidental detection is
*only* due to changes in Theta.

One Theta (the angular difference between the settings
of two spacelike separated polarizers) is analyzing the
relationship between the light incident on the polarizers
during a given coincidence interval.

4. I'm not necessarily *convinced* -- it's just one
approach. And, I'm only exploring the idea that
Bell doesn't apply to questions of locality and
realism.

No matter what is eventually learned, Bell's
analysis is extremely important.

I have the idea that local hidden variables exist
because it seems most parsimonious to assume
that the random variability of individual
results is coming from the emission events.
But, as you've noted, for all anyone knows, it
could be produced at/in the polarizer, or at/in the
detector, or between the emitter and the polarizer,
or between the polarizer and the detector, or ...

However, the setups and instruments are calibrated
very carefully, so the likelihood of something
other than the emission events being the cause
seems rather small.

The *relevant* global parameter (of the incident light)
for the *predictable* (that is, correlated wrt Theta)
joint results can't be varying randomly -- because
the number of coincidental detections per unit time
wrt a given Theta isn't random.

Bell's program was to see if the globalization of
an emission-produced variable parameter (that, if known,
would make individual results predictable) could duplicate
the qm corrlation function for singlet-type setups.

1. What you call a global parameter, is usually called a common wavefunction. This is simply the definition of entanglement. I guess I would agree that it has a global (non-local) element.

2. There is no Lambda. That is the explanation, and there is no difficulty.

3. This is a prediction of QM, specifically, what that value will be for any Theta. Competing theories need to yield the same predictions.

4. Bell applies, unless you provide non-standard definitions of locality and realism. Bell defines local reality as meaning there exists a definite value for a Theta other than the one actually observed. If you reject that definition, then naturally you won't follow Bell the rest of the way. However, that definition is fairly well respected with the physics community.

My conclusion is that you assume what you seek to prove. Your argument seems essentially identical to the logic of EPR, which also makes an unwarranted (but reasonable!) leap of logic in its final paragraph.

This discussion has reached the point at which I do not feel I can either add understanding or gain understanding. Thanks, and I will be sitting back and watching for a while.
 
Last edited:
  • #136
vanesch said:
In the case of the entanglement |0>|0> + |90>|90> yes, but your reasoning should also hold when I use a source with a SPECIFIC, fixed polarization (for instance when there are polarizers at each output of the source!). Quantum mechanically, this corresponds to a pure state, |0>|0> for instance.
As you claim that P(A,B) does not depend on the specific polarization direction in the case |0>|0> + |90>|90>, it should also not depend on it in the case |0>|0>. Now that's where I present you with the problem that in the case I have |0>|0> (and imagine that a and b are both 0, with theta 0) I will have P(A,B) = 1 (namely EVERYTHING gets through, on both sides), and if I now change a and b to 90 degrees, keeping |0> |0>, NOTHING gets through, and P(A,B) = 0.
So clearly P(A,B) cannot be only a function of theta, but must depend also on the angle between the polarization direction of the source and a and b, in this case. But according to your claims, it is always the same value, no matter what the incident polarization, as long as theta is a constant.

cheers,
Patrick.

I'm not sure what setup you're using. Are there two polarizers,
in series, on each side of the emitter?
 
  • #137
Sherlock said:
I'm not sure what setup you're using. Are there two polarizers,
in series, on each side of the emitter?


Alice Det <-- |POL Alice a| <-------|pol 0 deg| (source) |pol 0 deg| -----> |POL Bob b| --> Bob Det

Or you could use a source which emits already polarized light. It is hard to claim that putting in parallel polarizers will undo any "common" property... but even in that case you could use a polarized source.
 
  • #138
vanesch said:
In the case of the entanglement |0>|0> + |90>|90> yes, but your reasoning should also hold when I use a source with a SPECIFIC, fixed polarization (for instance when there are polarizers at each output of the source!). Quantum mechanically, this corresponds to a pure state, |0>|0> for instance.
As you claim that P(A,B) does not depend on the specific polarization direction in the case |0>|0> + |90>|90>, it should also not depend on it in the case |0>|0>. Now that's where I present you with the problem that in the case I have |0>|0> (and imagine that a and b are both 0, with theta 0) I will have P(A,B) = 1 (namely EVERYTHING gets through, on both sides), and if I now change a and b to 90 degrees, keeping |0> |0>, NOTHING gets through, and P(A,B) = 0.
So clearly P(A,B) cannot be only a function of theta, but must depend also on the angle between the polarization direction of the source and a and b, in this case. But according to your claims, it is always the same value, no matter what the incident polarization, as long as theta is a constant.

cheers,
Patrick.

P(A,B) is the rate at which coincidental results are recorded.
And, this rate will of course change as you vary the incident
polarization wrt the aligned polarizers.

But, this just changes the coincidental detection *visibility*
range.

The entanglement isn't affected by variations in the
incident global polarization. The polarization of the light
incident on the polarizers can be anything -- as long
as it's the same at both ends, then, with Theta = 0,
A and B will record identical detection attributes during
any given coincidence window.
 
Last edited:
  • #139
Sherlock said:
P(A,B) is the rate at which coincidental results are recorded.
And, this rate will of course change as you vary the incident
polarization wrt the aligned polarizers.

Ah, but you claimed before that this rate was something like 1/2 cos^2(theta), INDEPENDENT of the incident polarization lambda, which was an "irrelevant" quantity:

Sherlock said:
The coincidence rate at A and B with Theta = 0 is .5
no matter what the incident, common polarization is.

and now that rate of coincident results (remember that the total INCOMING flux is always the same, and if we are normalizing again on A or An, we find P(A,B) strongly varying) is OF COURSE dependent on the polarization detection.

Now if we work out quantum-mechanically what we are supposed to obtain when we have a |0>|0> state, and we test this with an <a| <b| measurement, we have the joint probability
P(A,B) = |<a|<b|0>|0>|^2 = |<a|0>|^2 |<b|0>|^2 = cos^2(a) cos^2(b)

(that's a quantummechanical prediction).

So if we now rotate this polarized source over lambda, we have the joint probability P(A,B ; lambda) = cos^2(a-lambda) cos^2(b-lambda), right ?

That's EXACTLY the same result as the semiclassical prediction I gave you a long time ago for incident light on both sides with identical polarization lambda: it is the double, and independent, application of Malus' law for each independent detector. But this time it is also the quantummechanical result for a polarized source in direction lambda. Both methods work in this case (semiclassical and pure quantum).

And now I come back to my initial reasoning: if you now assume that the "entangled" source is like this (semiclassical) source with polarization lambda, but where lambda is randomly varying from event to event, then (that's basic probability theory) the overall P(A,B) without knowing lambda, is of course the P(A,B ; lambda) weighted (integrated over) the probability distribution of lambda, p(lambda). And cylindrical symmetry then makes this p(lambda) = 1/2pi.

So, if you suppose that light from an entangled source is just "randomly polarized, but each time identical, semiclassical light", then you work out this weighting: P(A,B) = integral over lambda of p(lambda) x P(A,B ; lambda) and you find 1/8(2 - cos(2(a-b))). (or whatever it was that I got).

Saying things like that the polarization is "irrelevant" for P(A,B) is clearly wrong as you now see yourself, from the moment that the source is polarized.
It cannot be "irrelevant" for one case, and "of course dependent" in the other, when the analyzing technique is identical (and only the source changes, which was exactly what we were trying to analyze).

I rest my case.

cheers,
Patrick.

PS: the same simple technique gives us the right coincident rate in the case of the entangled state |psi> =1/sqrt(2) (|0>|0> + |90>|90>):

|<a|<b| psi>|^2 = 1/2 |<a|0><b|0> + <a|90><b|90>|^2 =
1/2 (cos(a) cos(b) + sin(a) sin(b))^2 = 1/2(cos(a-b))^2 = 1/2 cos^2 theta.
 
  • #140
vanesch said:
Now if we work out quantum-mechanically what we are supposed to obtain when we have a |0>|0> state, and we test this with an <a| <b| measurement, we have the joint probability
P(A,B) = |<a|<b|0>|0>|^2 = |<a|0>|^2 |<b|0>|^2 = cos^2(a) cos^2(b)

(that's a quantummechanical prediction).

So if we now rotate this polarized source over lambda, we have the joint probability P(A,B ; lambda) = cos^2(a-lambda) cos^2(b-lambda), right ?

That's EXACTLY the same result as the semiclassical prediction I gave you a long time ago for incident light on both sides with identical polarization lambda: it is the double, and independent, application of Malus' law for each independent detector. But this time it is also the quantummechanical result for a polarized source in direction lambda. Both methods work in this case (semiclassical and pure quantum).

And now I come back to my initial reasoning: if you now assume that the "entangled" source is like this (semiclassical) source with polarization lambda, but where lambda is randomly varying from event to event, then (that's basic probability theory) the overall P(A,B) without knowing lambda, is of course the P(A,B ; lambda) weighted (integrated over) the probability distribution of lambda, p(lambda). And cylindrical symmetry then makes this p(lambda) = 1/2pi.

So, if you suppose that light from an entangled source is just "randomly polarized, but each time identical, semiclassical light", then you work out this weighting: P(A,B) = integral over lambda of p(lambda) x P(A,B ; lambda) and you find 1/8(2 - cos(2(a-b))). (or whatever it was that I got).

Saying things like that the polarization is "irrelevant" for P(A,B) is clearly wrong as you now see yourself, from the moment that the source is polarized.
It cannot be "irrelevant" for one case, and "of course dependent" in the other, when the analyzing technique is identical (and only the source changes, which was exactly what we were trying to analyze).

I rest my case.

Ok it's relevant. :)

You've got a source producing entangled photon pairs
with the polarization unchanging from pair to pair.

You rotate polarizer_a, whose setting we'll
denote as p_a, to find the maximum
detection rate at A. Denote this setting as
MDR_a and the detection rate at MDR_a as mdr_a.
Denote the detection rate at A for any p_a as
dr_a. dr_a should vary (mdr_a --> 0) as
|p_a - MDR_a| varies (0 --> pi/2) as
the function,

dr_a = mdr_a(cos^2 |p_a - MDR_a|).

Using the same conventions at B,
if MDR_b = MDR_a, then if mdr_b = mdr_a,
then the rate of coincidental detection,
denoted as cd_AB should vary (mdr --> 0)
as |p_a - p_b| varies (0 --> pi/2) as
the function,

cd_AB = mdr(cos^2 |p_a - p_b|).


Now, if you rotate the aligned
polarizers so that mdr decreases
by say .125, then cd_AB will vary
(mdr-.125 --> .125mdr) as |p_a - p_b|
varies (0 --> pi/2) as the
function,

cd_AB = mdr[.125(1 + 2(cos^2 |p_a - p_b|))].

So, in order to keep the classical
notion of a definite global polarization
per emission as an explanation for Bell test
results, then it must be that the polarizer
at the end that initiates the coincidence
interval was aligned with the emission
polarization of the light incident on it.

(It seems likely to be so aligned
a few times per second out of the
millions of randomly polarized
emissions per second.)

And, since the light incident on the
other polarizer for that interval is
polarized via emission the same as
the light incident on the polarizer
at the detecting end, then you get
the qm prediction, and a physical
explanation for why the projection
works.

Do you see anything wrong with this?
 

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