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Jen2114
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Homework Statement
In a region of space there is an electric field E(vector E) that is in the x-direction and that has magnitude E=(663 N/(C*m))x
Find flux for this field through a square in xy plane at z=0 and with side length 0.330m . One side of the square is along the +x-axis and another side is along the +y-axis.
I understand setting up the integral but I do not understand why there is a y in the answer
Homework Equations
The Attempt at a Solution
ΦE= ∫Ecos∅dA , where phi is the angle between the normal area vector and the E field. In this case E-field and A are parallel so cos∅=1 . Thus integral reduces to ΦE=∫EdA. dA of a small piece of the square is determined by dy*dx.
Then, integral becomes ∫663x*dydx (from 0 to 0.330)
Final answer should be
(y*663x^2)/2 (from 0 to 0.330) so final answer is 11.91.
I understand anti derivative of x is x^2/2 but I am not understanding/seeing where the y factor comes from.
Thanks [/B]