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amninder15 said:Can someone please help me on this question. I tried to solve it by integrating 0.5*(1-3sin(θ)^2 from -Pi/2 to 0 but I didnt get the answer.
amninder15 said:Yea I made some silly mistake I think It goes from sin^-1(1/3) to Pi-sin^-1(1/3). But that looks ugly. Am I on right path.
The formula for finding the area enclosed by a polar curve is A = 1/2∫ab r2(θ) dθ, where r(θ) is the polar equation of the curve and a and b are the starting and ending values of θ.
To graph a polar curve, plot points by substituting different values of θ into the polar equation. Then, connect the points to create the shape of the curve. To find the area enclosed by the curve, use the formula A = 1/2∫ab r2(θ) dθ and evaluate the integral using calculus.
A positive value for the area enclosed by a polar curve represents the area inside the curve, while a negative value represents the area outside the curve. This is because the formula for finding the area uses absolute value to ensure a positive result.
Yes, the formula for finding the area enclosed by a polar curve can still be used if the curve crosses the origin. However, you may need to break the integral into smaller intervals and evaluate them separately to account for the curve crossing the origin.
Yes, there are other methods for finding the area enclosed by a polar curve, such as using Green's Theorem or converting the polar equation to rectangular form and using the formula for finding the area of a region bounded by a curve. However, the integral method is the most commonly used and most straightforward method.