How to make m1 the subject of the formula

In summary, an object with a total mass of 75kg ejects a smaller object to the left with a velocity of 7 ms-1 and a mass of m2. The original object then recoils backwards to the right with a velocity of -2 ms-1 and a mass of m1. Using the equations m2 + m1 = 75kg and m1*v1 + m2*v2 = 0, the mass of m1 can be calculated as total mass * velocity 2 / (velocity 2 - velocity 1). It is unclear how the expression -m1*v2 + m1*v1 = -total mass * v2 changes from a positive to a negative when factored.
  • #1
cykachu12
1
0
Homework Statement
an object has a total mass of 75kg and is stationary, it then ejects as a smaller object to the left with a velocity of(+ve direction)7 ms-1(v2) with a mass of m2 , the original object then recoils backwards to the right (-ve direction) at a velocity of -2 ms-1 and a mass of m1 .
calculate the mass of m1
Relevant Equations
m2 + m1 = 75kg
m1*v1+m2*v2=0
momentum before event = momentum after event
Homework Statement: an object has a total mass of 75kg and is stationary, it then ejects as a smaller object to the left with a velocity of(+ve direction)7 ms-1(v2) with a mass of m2 , the original object then recoils backwards to the right (-ve direction) at a velocity of -2 ms-1 and a mass of m1 .
calculate the mass of m1
Homework Equations: m2 + m1 = 75kg
m1*v1+m2*v2=0
momentum before event = momentum after event

the answer is total mass * velocity 2
m1 = ------------------------------
velocity 2 - velocity 1 I don't get how on the 2nd attempt i did (in pencil) how -m1*v2 + m1*v1 = -total mass * v2
goes from a + to a - when I factorise.
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  • #2
Because ##-m \cdot (v-w)= (-m)\cdot v - (-m)\cdot w = -mv -(-mw) = -mv+mw##.
 

What does it mean to make m1 the subject of the formula?

Making m1 the subject of the formula means rearranging the equation to solve for m1. This allows us to express m1 in terms of the other variables in the formula.

Why is it important to make m1 the subject of the formula?

Making m1 the subject of the formula allows us to easily manipulate the equation to solve for different variables or to find the value of m1 in different scenarios.

How do you make m1 the subject of the formula?

To make m1 the subject of the formula, we need to isolate m1 on one side of the equation by performing inverse operations on the other variables. This involves using algebraic rules such as the distributive property and combining like terms.

Can you provide an example of making m1 the subject of the formula?

Sure, let's say we have the formula F = m1a + m2b, and we want to make m1 the subject. We can do this by first subtracting m2b from both sides to get F - m2b = m1a. Then, we divide both sides by a to get m1 = (F - m2b)/a. Now, m1 is the subject of the formula.

What are some common mistakes to avoid when making m1 the subject of the formula?

One common mistake is forgetting to perform the same operation on both sides of the equation. Another mistake is not following the correct order of operations, which can lead to an incorrect solution. It's important to double check your work and simplify the equation before considering it the final answer.

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