The voltage across resistor 2 is the same as the voltage across the capacitor. Since the voltage across parallel circuits is the same, we only need to use the voltage divider rule among Resistor 1 and the resistors in parallel. Doing this however, doesn't result in the correct answer.Nidum said:
anonx12 said:
A capacitor is an electronic component that stores and releases electrical energy. It is made up of two conductive plates separated by an insulating material, known as a dielectric. When a voltage is applied, one plate becomes positively charged and the other becomes negatively charged. This creates an electric field between the plates, which allows the capacitor to store energy.
When a voltage is applied to a capacitor, it charges up until the potential difference between the plates is equal to the applied voltage. Once this happens, the capacitor stops charging and begins to store the electrical energy in the form of an electric field. When the voltage is removed, the capacitor discharges and releases the stored energy.
The voltage across a capacitor is the potential difference between the two plates. Since a capacitor stores electrical energy, the voltage across it will vary depending on the amount of charge stored. The higher the charge, the higher the voltage will be.
The voltage across a capacitor can be found by using the formula V = Q/C, where V is the voltage in volts, Q is the charge in coulombs, and C is the capacitance in farads. This formula shows that the voltage across a capacitor is directly proportional to the charge stored and inversely proportional to the capacitance.
The voltage across a capacitor is important because it determines how much energy is stored in the capacitor. This can affect the performance of electronic circuits and devices, as well as the overall efficiency of a system. It is also important to consider the voltage across a capacitor when designing circuits to ensure that the voltage does not exceed the maximum rating of the capacitor.
