Inductive Current Coupling Between Two Coils

In summary: Sorry for the confusion, I am not able to provide a summary for this conversation as it involves technical information and questions. In summary, the conversation discusses a question related to the current, power, and emf in a transformer circuit. The answer options are not clearly stated and there are some assumptions that need to be made in order to answer the question. Ultimately, it is concluded that there is not enough information to determine a matching answer.
  • #1
hidemi
208
36
Homework Statement
In the diagram, assume that all the magnetic field lines generated by coil 1 pass through coil 2. Coil 1 has 100 turns and coil 2 has 400 turns. Then:


A. the power supplied to coil 1 is equal to the power delivered by coil 2

B. the emf around coil 1 will be 1/4 the emf around coil 2

C. the current in coil 1 will be 1/4 the current in coil 2

D. the emfs will be the same in the two coils

E. none of the above


ans: E
Relevant Equations
ε = -N * dΦ/dt = - L * dI/dt
In this case, we do not know any information about the current, right?
Therefore, there is no matching answer.
 

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  • #2
hidemi said:
A. the power supplied to coil 1 is equal to the power delivered by coil 2

B. the emf around coil 1 will be 1/4 the emf around coil 2

C. the current in coil 1 will be 1/4 the current in coil 2

D. the emfs will be the same in the two coils

E. none of the above
.
ans: E
.
In this case, we do not know any information about the current, right?
Therefore, there is no matching answer.
Well, no one else has answered, so I’ll have a go. I think I see what’s going on, but will be happy to be corrected. Sorry if what follows is a bit long-winded.

Is that the complete, exact wording of the question? A few assumptions (which should have been explicitly stated in the question) are probably needed:
- the question refers to the time after the switch is closed;
- the cell and coil-windings are ideal (zero resistance);
- the galvanometer has some non-zero resistance (so the secondary circuit is not a short-circuit).

In addition, the question refers to “the emf around coil 1”. This is confusing – does it mean the cell’s emf, or the back-emf generated in coil 1 when a current flows through it, or something else?

You said: “… we do not know any information about the current, right? Therefore, there is no matching answer.“

That’s not really correct. We can infer certain things about the relationship between primary and secondary currents. And if we don’t even consider currents, we can still use conservation of energy and knowledge of flux in transformers to help us.

You might want to consider these 2 points/questions first:

Q1. Passing a current through a coil (inductance L) sets up a magnetic field which stores energy. If a resistor (R) is then connected across the coil, current flows and decays with time-constant L/R. (in a similar way that a charged capacitor discharges through a resistor). Is that relevant here?

Q2. Are the time-constants for the primary and secondary circuits equal? If not, will this have any signficant effects?

Then consider each answer-option; here are some hints:
A: This option refers to ‘power’, not energy. Is this significant?
B: EDIT: B is a confusing option - are the emfs referred to covering the same time period? This is highly ambiguous.
C: Is the answer to this option related to the answer to option A?
D. Is the answer to this option related to the answer to option B?

You can post your answers to Q1, Q2 and your analysis of A, B, C and D if you want them checked.

If you can sort your way through that lot, you will find option E appears to be correct!
 
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  • #3
Steve4Physics said:
Well, no one else has answered, so I’ll have a go. I think I see what’s going on, but will be happy to be corrected. Sorry if what follows is a bit long-winded.

Is that the complete, exact wording of the question? A few assumptions (which should have been explicitly stated in the question) are probably needed:
- the question refers to the time after the switch is closed;
- the cell and coil-windings are ideal (zero resistance);
- the galvanometer has some non-zero resistance (so the secondary circuit is not a short-circuit).

In addition, the question refers to “the emf around coil 1”. This is confusing – does it mean the cell’s emf, or the back-emf generated in coil 1 when a current flows through it, or something else?

You said: “… we do not know any information about the current, right? Therefore, there is no matching answer.“

That’s not really correct. We can infer certain things about the relationship between primary and secondary currents. And if we don’t even consider currents, we can still use conservation of energy and knowledge of flux in transformers to help us.

You might want to consider these 2 points/questions first:

Q1. Passing a current through a coil (inductance L) sets up a magnetic field which stores energy. If a resistor (R) is then connected across the coil, current flows and decays with time-constant L/R. (in a similar way that a charged capacitor discharges through a resistor). Is that relevant here?

Q2. Are the time-constants for the primary and secondary circuits equal? If not, will this have any signficant effects?

Then consider each answer-option; here are some hints:
A: This option refers to ‘power’, not energy. Is this significant?
B: EDIT: B is a confusing option - are the emfs referred to covering the same time period? This is highly ambiguous.
C: Is the answer to this option related to the answer to option A?
D. Is the answer to this option related to the answer to option B?

You can post your answers to Q1, Q2 and your analysis of A, B, C and D if you want them checked.

If you can sort your way through that lot, you will find option E appears to be correct!
Thanks for stating multiple presumptions to help me think through this question.
I think I got it.
 
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1. What is inductive current coupling between two coils?

Inductive current coupling between two coils is a phenomenon in which an alternating current flowing through one coil induces a current in a nearby coil without any physical connection between the two coils.

2. How does inductive current coupling work?

Inductive current coupling works through the principle of electromagnetic induction. When an alternating current flows through one coil, it creates a changing magnetic field that passes through the nearby coil, inducing a current in the second coil.

3. What are the applications of inductive current coupling?

Inductive current coupling has various applications, including wireless power transfer, signal transmission, and data communication. It is also used in transformers and electric motors.

4. What factors affect the strength of inductive current coupling?

The strength of inductive current coupling is affected by the number of turns in the coils, the distance between the coils, and the frequency of the alternating current. A higher number of turns and a closer distance between the coils result in a stronger coupling.

5. How is inductive current coupling different from capacitive coupling?

Inductive current coupling and capacitive coupling are both methods of transferring energy wirelessly. However, inductive current coupling uses magnetic fields to transfer energy, while capacitive coupling uses electric fields. Additionally, inductive coupling is more efficient for longer distances, while capacitive coupling is more efficient for shorter distances.

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