- #1
Pushoam
- 962
- 51
I am asking this because ∇ is also considered as a vector in some cases. Considering it as a vector in this case ,too,
( ∇× E).E = (- ∂ B/∂t).E = - ∂ (B.E)/∂t =0
Since B and E could be arbitrarily dependent on t,
B.E = 0
where B and E are magnetic and electric fields respectively.
This means that B and E are always perpendicular to each other.
( ∇× E).E = (- ∂ B/∂t).E = - ∂ (B.E)/∂t =0
Since B and E could be arbitrarily dependent on t,
B.E = 0
where B and E are magnetic and electric fields respectively.
This means that B and E are always perpendicular to each other.