The symbols on the left side don't make sense. The right side is useful, but you should probably derive those equations to be sure.Joel Kee said:Is the formula for voltage drop across capacitor opposite of the formula for resistor, where resistor is R1=R1/(R1+R2) while capacitor is C1=C2/(C1+C2)?
My bad, the eqs are supposed to be multiplied with the total voltage.mfb said:The symbols on the left side don't make sense. The right side is useful, but you should probably derive those equations to be sure.
Still your bad. R1=R1/(R1+R2) ? Etc.Joel Kee said:My bad, the eqs are supposed to be multiplied with the total voltage.
V1=[R1/(R1+R2)]Vrude man said:Still your bad. R1=R1/(R1+R2) ? Etc.
Voltage drop across a capacitor is the decrease in voltage that occurs when a capacitor is connected to a circuit. This decrease is due to the capacitor's ability to store and release electrical charge.
Voltage drop across a capacitor can be calculated using the equation V = Q/C, where V is the voltage drop, Q is the charge stored on the capacitor, and C is the capacitance of the capacitor.
The voltage drop across a capacitor can be affected by the size of the capacitor, the amount of charge stored on the capacitor, and the frequency of the AC voltage applied to the capacitor.
Voltage drop across a capacitor is important because it affects the overall performance of a circuit. It can impact the stability of the circuit, the efficiency of power transfer, and the accuracy of measurements in the circuit.
Voltage drop across a capacitor can be reduced by increasing the capacitance or decreasing the frequency of the AC voltage applied to the capacitor. It can also be reduced by using multiple capacitors in parallel to increase the overall capacitance.