- #1
Bashyboy
- 1,421
- 5
Homework Statement
[itex]\int\frac{1}{\sqrt{16-x^2}}dx[/itex]
Homework Equations
[itex]csc\theta=\frac{4}{\sqrt{16-x^2}}[/itex]
[itex]4cos\theta=x[/itex]
[itex]-4sin\theta d\theta=dx[/itex]
[itex]\theta=arccos(\frac{x}{4})[/itex]
The Attempt at a Solution
Using these facts, I concluded that the integral, after all of the substitution, was
[itex]-arccos(\frac{x}{4})[/itex] but the actual answer is the arcsin