- #1
MozAngeles
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Homework Statement
Let T: P4--->P3 be a linear transformation given by T(p)=p'. What is the kernel of T?
Homework Equations
The Attempt at a Solution
T(a0+a1+a2x2+a3x3+a4x4)=a1+2a2x+3a3x2+4a4x3
Ker(T)= { T(p)=0}
so, a1+2a2x+3a3x2+4a4x3=0
then a1=2a2x+3a3x2+4a4x3
Ker(T)= { (-2,1,0,0), (-3,0,1,0), (-4,0,0,1)}
I solved this based off an example from class. But when I checked the dim[Ker(T)]= 3 and the dim[Rng(T)]=4 since my Rng(T)= {1,x,x2,x3} and dim[P4]=5
using general rank nullity theorem I have 7=5, which doesn't make sense. So I'm wondering where I went wrong.
Thank you for your help.