Losses in Power Devices (IGBT)

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In summary, to determine Ton (turn on time) for a SiC IGBT power device, one must first determine the voltage used to turn on the gate, as this affects the voltage seen across the collector to emitter junction. This can be found by reading the voltage from the junction curves on the data sheet. The power losses for the device can then be calculated by multiplying the voltage drop across the CE by the current flow through the gate, which is determined by the circuit load. Iteration of the circuit may be necessary for accuracy.
  • #1
billy fok
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In power device, there will be losses.. my device is SiC IGBT.

i know how to find Toff = toff + tf base on datesheet..
but i don't know how to find Ton = doff +tr.

http://ixapps.ixys.com/DataSheet/DS100140A_IXGH48N60B3C1.pdf

can someone guide me along..
 
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Read the data sheet and determine what the voltage that you will use to turn on the gate, the larger the voltage, the less voltage is actually seen by the junction across the collector to the emitter is when the device is on. This voltage needs to be determined, then read the voltage from the junction curves to determine the volt/amp curve. Power losses equal the voltage drop across the CE multiplied by the current flow through the gate. Your actual circuit load will determine the current flow which will then be used to determine your loss in the transistor.

You may have to iterate your circuit one or two cycles ie crunch the numbers one or two times to approach the accuracy you need.
 
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Related to Losses in Power Devices (IGBT)

1. What are IGBTs and why are they important in power devices?

IGBT stands for Insulated Gate Bipolar Transistor, and it is a type of semiconductor device used for power switching and amplification. This component is important because it combines the high efficiency of a MOSFET with the high current and voltage capabilities of a bipolar transistor.

2. How do losses occur in IGBTs?

Losses in IGBTs occur due to several factors such as conduction losses, switching losses, and gate drive losses. Conduction losses occur when the IGBT is conducting current, while switching losses occur during the transition from the on-state to the off-state. Gate drive losses are caused by the energy required to turn the IGBT on and off.

3. What is the impact of losses in IGBTs?

Losses in IGBTs can lead to reduced efficiency, increased heat generation, and decreased reliability. This can result in higher costs for cooling and maintenance, as well as shorter lifetimes for the power devices.

4. How can losses in IGBTs be reduced?

There are several ways to reduce losses in IGBTs. One method is to use a higher switching frequency, which can reduce the conduction losses. Another method is to use advanced packaging and cooling techniques to dissipate heat more efficiently. Additionally, using optimized gate drive circuits and reducing parasitic inductances can also help reduce losses.

5. Are there any future developments in reducing losses in IGBTs?

Yes, research is ongoing to develop new materials and designs for IGBTs that can further reduce losses and improve efficiency. Some examples include the use of silicon carbide and gallium nitride as semiconductor materials, as well as the development of new cell structures and packaging techniques.

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