Magnetic forces on current-carrying wires

In summary, the conversation discusses a problem involving the direction and magnitude of the resultant magnetic force acting on wire X due to the magnetic fields from wires Y and Z. The direction of the force on X is given as pointing towards X, causing confusion and prompting a discussion on how to approach the problem. Eventually, it is determined that the force per unit length acting on X is 0.50 mN/m, not 0.50 m, and the correct interpretation of the direction of the force is towards the positive x-axis.
  • #1
hooman
22
0
Homework Statement
Three long straight thin conductors X, Y, Z lie on the same plane and are parallel to each
other as shown in Figure 1.Current flows in each conductor in the direction as shown. The
earth’s magnetic field may be neglected. The resultant magnetic force per unit length acting
on X is 0.50 mN m-1 , pointing towards X.
a) Is the direction of the current in Z shown in the diagram correct? Explain.
b) Determine the current in Z.
Relevant Equations
F/l= 0.50
please correct me if I'm wrong.

is it for the question b, F/l= 0.50 right? does that mean the resultant magnetic force at X is determine by the force at Y and Z? do I need to consider the direction to solve the equation? first step to know the direction of each conductors I use the right hand rule and I already get the direction of the forces for each conductors then I don't know whether I need to consider the direction like positive or negative to put in the equation. Please help me, thank you.
 

Attachments

  • IMG_20200102_001909.jpg
    IMG_20200102_001909.jpg
    21.1 KB · Views: 284
Physics news on Phys.org
  • #2
hooman said:
is it for the question b, F/l= 0.50 right?
That's given as the force per unit length acting on wire X. Although I am not sure what "pointing towards X" means. (What's the direction of the force on X? up, down, left, right, into the page, out of the page?)
hooman said:
does that mean the resultant magnetic force at X is determine by the force at Y and Z?
The resultant force on X is due to the magnetic fields from Y and Z that act on X.
 
  • #3
Doc Al said:
That's given as the force per unit length acting on wire X. Although I am not sure what "pointing towards X" means. (What's the direction of the force on X? up, down, left, right, into the page, out of the page?)

The resultant force on X is due to the magnetic fields from Y and Z that act on X.
direction force of X is to the left
 
  • #4
hooman said:
direction force of X is to the left
That's what I assumed they meant. (But that could have been stated more clearly.)

So, what's the force per length on X due to the current in Y?
 
  • #5
Doc Al said:
That's what I assumed they meant. (But that could have been stated more clearly.)

So, what's the force per length on X due to the current in Y?
you mean the value or what?
 
  • #6
hooman said:
you mean the value or what?
Yes. Magnitude and direction.
 
  • #7
Doc Al said:
Yes. Magnitude and direction.
2.5x10^-4 , direction to the left
 
  • #8
hooman said:
2.5x10^-4 , direction to the left
So what additional force must wire Z exert on X to produce the given resultant?
 
  • #9
hooman said:
The resultant magnetic force per unit length acting
on X is 0.50 mN m-1 , pointing towards X.
I find this statement confusing (not your fault). The magnetic force per unit length acting on wire X must be perpendicular to the wire marked X. As such, the force must point either away from wire Y (or Z) or towards it. "Towards X" makes no sense to me. Regardless of this, how do you propose to approach the problem if the direction of the force on X were given to you in a way that makes sense?
 
  • #10
Doc Al said:
So what additional force must wire Z exert on X to produce the given resultant?
is it 0.49975 ?
 
  • #11
kuruman said:
I find this statement confusing (not your fault). The magnetic force per unit length acting on wire X must be perpendicular to the wire marked X. As such, the force must point either away from wire Y (or Z) or towards it. "Towards X" makes no sense to me. Regardless of this, how do you propose to approach the problem if the direction of the force on X were given to you in a way that makes sense?
i would consider the direction of force is away from Y
 
  • #12
hooman said:
is it 0.49975 ?
Note that the resultant (total) force/length on X is given as 0.5 mN/m = 0.5 10^(-3) N/m.
 
  • #13
kuruman said:
I find this statement confusing (not your fault). The magnetic force per unit length acting on wire X must be perpendicular to the wire marked X. As such, the force must point either away from wire Y (or Z) or towards it. "Towards X" makes no sense to me. Regardless of this, how do you propose to approach the problem if the direction of the force on X were given to you in a way that makes sense?
I agree with your comments about the confusing wording of the direction of the force. I wonder what book this is from? (The best I could assume is that they meant from Y or Z toward X. Not clear at all.)
 
  • #14
Doc Al said:
I agree with your comments about the confusing wording of the direction of the force. I wonder what book this is from? (The best I could assume is that they meant from Y or Z toward X. Not clear at all.)
Another interpretation might be "towards the positive x-axis", i.e. to the right.
 
  • #15
kuruman said:
Another interpretation might be "towards the positive x-axis", i.e. to the right.
Indeed!
 
  • #16
Doc Al said:
Note that the resultant (total) force/length on X is given as 0.5 mN/m = 0.5 10^(-3) N/m.
i see, i thought the m here is metre. so i mistaken here. that's why when i do the solution i find it weird
 
  • #17
Doc Al said:
I agree with your comments about the confusing wording of the direction of the force. I wonder what book this is from? (The best I could assume is that they meant from Y or Z toward X. Not clear at all.)
this is my assignment's question
 
  • #18
Doc Al said:
Note that the resultant (total) force/length on X is given as 0.5 mN/m = 0.5 10^(-3) N/m.
so that means that resultant F/l is the sum of F/l from Y and from Z right?
 
  • #19
hooman said:
so that means that resultant F/l is the sum of F/l from Y and from Z right?
Correct.
 
  • #20
hooman said:
this is my assignment's question
Yes, it is that. However it's like giving you the equation ##y = 3 + x## and asking you to find ##x## given that the absolute value of ##y## is 5. There are two answers.
 
  • #21
Doc Al said:
Correct.
the question a , it ask for the direction of current Z correct or not. how to know it?
 
  • #22
hooman said:
the question a , it ask for the direction of current Z correct or not. how to know it?
If you know how much F/l wire Z must contribute, then you can figure out what direction its current must have.
 
  • #23
Doc Al said:
If you know how much F/l wire Z must contribute, then you can figure out what direction its current must have.
the F/l wire Z is 2.5x10^-4 also. the direction is correct?
 
  • #24
kuruman said:
Yes, it is that. However it's like giving you the equation ##y = 3 + x## and asking you to find ##x## given that the absolute value of ##y## is 5. There are two answers.
the question a , it ask for the direction of current Z correct or not. how to know it?
 
  • #25
hooman said:
the question a , it ask for the direction of current Z correct or not. how to know it?
That is what it is asking. To know the direction of the current, you need to know the direction of the force on wire X. This direction could be to the left or to the right. The statement of the problem says "towards X" which is neither to the left nor to the right.
 
  • #26
All about working out the force from each wire on X, the you know which way the current should be..
 

Attachments

  • 3 wire.pdf
    264.9 KB · Views: 129
  • #27
kuruman said:
That is what it is asking. To know the direction of the current, you need to know the direction of the force on wire X. This direction could be to the left or to the right. The statement of the problem says "towards X" which is neither to the left nor to the right.
do you think it make sense if I said the "towards X" in the statement means the direction of force on X by Z? because it is impossible for the force on X by Y to be towards X as the current is in different direction. what do you think?
 
  • #28
hooman said:
do you think it make sense if I said the "towards X" in the statement means the direction of force on X by Z? because it is impossible for the force on X by Y to be towards X as the current is in different direction. what do you think?
No, it does not mean the direction of force on X by Z. The problem states clearly that it is the resultant on X, that is the sum of forces by Y and Z.
 
  • #29
MartinCarr said:
All about working out the force from each wire on X, the you know which way the current should be..
so, you minus the Fy and Fz because it is in different direction? what do you mean by the 2 current must in opposite direction? which current that you mean? X and Y or X and Z?
 
  • #30
See the attached file on the above post..
 
  • #31
MartinCarr said:
See the attached file on the above post..
i've already seen it but i don't understand. can you please explain it to me based on the question i asked above.
 
  • #32
How about answering the question I posed earlier?
Doc Al said:
So what additional force must wire Z exert on X to produce the given resultant?
You are given the resultant F/L on wire X. You've calculated the contribution from wire Y. So, what must be the contribution from wire Z? That will tell you the direction of the current in Z and allow you to calculate the magnitude of that current.
 
  • #33
Doc Al said:
How about answering the question I posed earlier?

You are given the resultant F/L on wire X. You've calculated the contribution from wire Y. So, what must be the contribution from wire Z? That will tell you the direction of the current in Z and allow you to calculate the magnitude of that current.
2.5x10^-4 . is it right?
 
  • #34
Did you work this out or do you need me to explain more?
 
  • #35
hooman said:
2.5x10^-4 . is it right?
Don't just give a numeric answer. Describe how you got your answer. And what does that tell you about the direction and magnitude of the current through Z?
 

Similar threads

  • Introductory Physics Homework Help
Replies
7
Views
1K
Replies
2
Views
89
  • Introductory Physics Homework Help
Replies
4
Views
286
  • Introductory Physics Homework Help
Replies
6
Views
372
  • Introductory Physics Homework Help
Replies
8
Views
435
  • Introductory Physics Homework Help
Replies
3
Views
213
  • Introductory Physics Homework Help
Replies
12
Views
1K
  • Introductory Physics Homework Help
Replies
5
Views
481
  • Introductory Physics Homework Help
Replies
14
Views
1K
  • Introductory Physics Homework Help
Replies
1
Views
789
Back
Top