How Do Measurements Affect GHZ States?

In summary, the GHZ state is a superposition of two states, ##|000\rangle## and ##|111\rangle##, and the possible outcomes of measurements are the eigenstates of ##\sigma_x## and ##\sigma_y##. To find the probabilities of these outcomes, you can use the formula $$P = | \langle aaa|bbb\rangle|^2$$, where ##|aaa\rangle## is the initial state and ##|bbb\rangle## is the final state.
  • #1
EightBells
11
1
Homework Statement
We are going to perform measurements using the following four operators: $$\Sigma_{XYY} = \sigma_x \sigma_y \sigma_y$$
$$\Sigma_{YXY} = \sigma_y \sigma_x \sigma_y$$
$$\Sigma_{YYX} = \sigma_y \sigma_y \sigma_x$$
$$\Sigma_{XXX} = \sigma_x \sigma_x \sigma_x$$
where ##\sigma_{\rho}^{\alpha} = |\rho\rangle \langle \rho| - |-\rho\rangle \langle -\rho|## is the operator for qubit α and ρ = {x, y}. If the three qubits form the GHZ state, what are possible outcomes of the measurements for all
four operators and what are their probabilities? Calculate the expectation values of each operator above with respect to the GHZ state. Explain the importance of this result.
Relevant Equations
n/a
Here's what I think I understand:

First off, the GHZ state ##|GHZ \rangle = \frac {|000\rangle+|111\rangle} {\sqrt 2}##, and ##\sigma_x## and ##\sigma_y## are the usual Pauli matrices, so the four operators are easy to calculate in Matlab.

I'm thinking the expectation values of each operator with respect to the GHZ state should be $$\langle GHZ|\Sigma|GHZ\rangle$$ for each of the operators ##\Sigma##.

What I'm unsure of is, what are the possible outcomes of the measurements? Is this asking for specific states that could be the result of the measurement? Also what state am I starting from, the GHZ state, ground state ##|000\rangle##?

Once I know the outcomes (i.e. possibly certain states), do I then find the probabilities with those via the typical method, $$P = | \langle aaa|bbb\rangle|^2$$, for some states ##\langle aaa|## and ##|bbb\rangle##? What are those states however? I would think I'm looking for the probability of starting in the GHZ state and ending up in the outcome state, so ##|bbb\rangle = |GHZ\rangle## and ##\langle aaa| = \langle outcome|##?
 
Physics news on Phys.org
  • #2
Hello,

Thank you for your post. You are correct in your understanding of the GHZ state and the operators ##\sigma_x## and ##\sigma_y##. The expectation values of these operators with respect to the GHZ state can be calculated using the formula you provided, $$\langle GHZ|\Sigma|GHZ\rangle$$.

To answer your question about the possible outcomes of the measurements, it is important to note that the GHZ state is a superposition of two states, ##|000\rangle## and ##|111\rangle##. This means that the possible outcomes of the measurements are the states that make up the superposition, ##|000\rangle## and ##|111\rangle##. In other words, the possible outcomes are the eigenstates of the operators ##\sigma_x## and ##\sigma_y##.

To find the probabilities of these outcomes, you can use the formula you provided, $$P = | \langle aaa|bbb\rangle|^2$$, where ##|aaa\rangle## is the initial state and ##|bbb\rangle## is the final state. In this case, the initial state is the GHZ state, ##|GHZ\rangle##, and the final states are the eigenstates of ##\sigma_x## and ##\sigma_y##, which are ##|000\rangle## and ##|111\rangle##.

I hope this helps clarify your understanding. Please let me know if you have any further questions.
 

1. What is a GHZ state?

A GHZ state, or Greenberger-Horne-Zeilinger state, is a type of quantum state that involves multiple particles being entangled with each other. This means that the state of one particle is dependent on the state of the other particles, even if they are physically separated.

2. How are GHZ states measured?

GHZ states are typically measured using quantum state tomography, which involves performing multiple measurements on the particles to determine their quantum state. This can also be done using Bell state measurements, which involve measuring the entanglement between two particles.

3. What is the significance of GHZ states in quantum computing?

GHZ states are important in quantum computing because they can be used to perform certain quantum algorithms more efficiently than classical computers. They can also be used for secure communication, as any attempt to intercept the communication would disrupt the entanglement and be detected.

4. How are GHZ states created in the lab?

GHZ states can be created in the lab using various methods, such as using laser pulses to entangle particles or using superconducting circuits. These methods involve carefully controlling the state of each particle to create the desired entanglement.

5. What are the potential applications of GHZ states?

Aside from their use in quantum computing and communication, GHZ states have potential applications in fields such as cryptography, metrology, and quantum simulation. They may also have implications for our understanding of fundamental physics and the nature of reality.

Similar threads

  • Advanced Physics Homework Help
Replies
9
Views
239
  • Advanced Physics Homework Help
Replies
1
Views
767
  • Advanced Physics Homework Help
Replies
3
Views
1K
  • Advanced Physics Homework Help
Replies
1
Views
1K
  • Advanced Physics Homework Help
Replies
3
Views
1K
  • Advanced Physics Homework Help
Replies
12
Views
2K
  • Advanced Physics Homework Help
Replies
14
Views
1K
  • Advanced Physics Homework Help
Replies
6
Views
1K
  • Advanced Physics Homework Help
Replies
12
Views
2K
Replies
3
Views
2K
Back
Top