- #1
Flyingwing12
- 41
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I was piddling with my meter and graphing calculator and came up with this equation
y= .08x+.14
This equation uses the number of batteries for X, and the Amp draw through a light bulb for Y.
The results are theoretical past 4 batteries.
The batteries were 1.29 v when the experiment began.
The real question here is about resistance.
Outside here it is about 80 degrees F, the ohmmeter showed 1.3 ohms from the light-bulb. The light bulb, using Ohms law, will have a resistance of ~11.4667 ohms when ~5.16 V are put to it. Meaning an amp draw of ~.45A
*With this initial resistance and final resistance being known, can I use a linear model to find the resistance of the bulb for each individual cell?*
How would this model be constructed?
If a graph were to be constructed it would start at (0,1.3) and end at (4, 11.46667). Is there any digital way of finding the missing values?
Kind of a math question isn't it?
y= .08x+.14
This equation uses the number of batteries for X, and the Amp draw through a light bulb for Y.
The results are theoretical past 4 batteries.
The batteries were 1.29 v when the experiment began.
The real question here is about resistance.
Outside here it is about 80 degrees F, the ohmmeter showed 1.3 ohms from the light-bulb. The light bulb, using Ohms law, will have a resistance of ~11.4667 ohms when ~5.16 V are put to it. Meaning an amp draw of ~.45A
*With this initial resistance and final resistance being known, can I use a linear model to find the resistance of the bulb for each individual cell?*
How would this model be constructed?
If a graph were to be constructed it would start at (0,1.3) and end at (4, 11.46667). Is there any digital way of finding the missing values?
Kind of a math question isn't it?
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