- #1
thebert010
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Homework Statement
In Figure 27-72, an ideal battery with an emf of = 14.0 V is connected to a network of resistances with R1 = 7.00 , R2 = 12.0 , R3 = 4.00 , R4 = 1.00 and R5 = 6.00 . What is the potential difference across R5?
FIGURE:
|----**R1**---|
| |---**R3**---|
|---**R2**----| |
| |--|
| | |
|---**R4**-------**R5**----| |
| | |
|-----------+\emf\-----------|--|
Homework Equations
V=iR
Parallel R = R12 = (1/R1 + 1/R2)^-1
Series R = R12 = R1 + R2
The Attempt at a Solution
I just typed a realllllly long attempt at my solution and the page crashed and I lost everything, and I'm at work...so briefly:
R1 and R2 are parallel so R12 = (1/7 + 1/12)^-1 = 4.42ohm
R12 and R3 are in Series so R123 = 4.42ohm + 4ohm = 8.42 ohm
R4 and R5 are in Series so the same = R45 = 7ohm
R123 and R45 are parallel so R12345 = (1/8.42 + 1/7)^-1 = 3.822 ohm
after attempting various things involving V = iR (where R's in Series have same i and R's parallel have same V) I cannot seem to get the potential difference across R5...PLEASE HELPPPPPP
thanks so much