- #1
MathewsMD
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Given a racemic mixture with both isomers being optically active, why is it that light can still pass through? If I am not mistaken (this may be completely wrong): the two isomers of a compound, when optically active, polarize light in a plane perpendicular the other. (If this is wrong, please tell me, since that will clear a lot of confusion.)
Given the above statement, if lights was propagated through two different molecules that polarize light in perpendicular planes, wouldn't there be no resultant light exiting the medium?
Given the above statement, if lights was propagated through two different molecules that polarize light in perpendicular planes, wouldn't there be no resultant light exiting the medium?