- #1
Rijad Hadzic
- 321
- 20
Homework Statement
Determine singular points of given DE. Classify as regular or irregular
[itex] (x^3 -2x^2 + 3x)^2 y'' + x(x-3)^2 y' + (-x-1)y = 0 [/itex]
Homework Equations
The Attempt at a Solution
From the polynomial infront of y'' I get
[itex] x^2 (x^2 -2x + 3)^2 [/itex]
right out of the bat I can see that x = 0 is going to be a regular point.
the zeros of [itex] x^2 -2x +3 = 1\frac +- \frac {8^{1/2}}{2} [/itex]
so since the denominator of y' will have [itex] x^2 -2x +3 = 1\frac +- \frac {8^{1/2}}{2} [/itex] to the second power, can I say that [itex] x^2 -2x +3 = 1\frac +- \frac {8^{1/2}}{2} [/itex] are the irregular points then?