Relativistic doppler effect for light

In summary, the problem involves a star moving at 0.2c and emitting light with a maximum intensity at a wavelength of 500nm. The spacing between wave crests for emitted light is calculated to be ##\lambda_{ahead} = \lambda (1 - \frac{v}{c})## for light ahead of the star and ##\lambda_{behind} = \lambda (1 + \frac{v}{c})## for light behind the star in the star's frame of reference. These lengths are then transformed to the observers' frame of reference using ##L_{proper} = \gamma L##. The frequency of light in the star's frame of reference is calculated to be ##f=\frac{v
  • #1
Samuelriesterer
110
0
Problem statement, work done, relative equations:

I am unsure if I got this problem right, especially part (e)

A star is moving at 0.2c along the x axis. The star is moving away from observer A and toward observer B. The star emits light with a maximum intensity at wavelength 500nm.

(a) Calculate the spacing between wave crests for emitted light with λ= 500nm ahead of the star and behind it in the star's frame of reference.

##\lambda_{ahead} = \lambda (1 - \frac{v}{c})##
##\lambda_{behind} = \lambda (1 + \frac{v}{c})##

(b) Transform these lengths to the observers' frame of reference.

##L_{proper} = \gamma L##

(c) Calculate the frequency of the light in the star's frame of reference.

##f=\frac{v}{\lambda} = \frac{c}{500 nm}##

(d) Calculate the frequency measured by observers A and B. This would be the time interval between receiving two successive wave crests (no relativity needed).

##f' = \frac{v}{\lambda} = \frac{.2c}{L_{proper}}##

(e) Suppose observer A is moving toward the star (and Observer B) at 0.4c. Recalculate the frequency observer A measures. You will need to recalculate the length contraction given the new relative speed and then figure the time between encountering the wave crests. What you have done is calculate the Doppler shift for light.

##u’ = \frac{u+v}{1-\frac{uv}{c^2}}=\frac{.2c+.4c}{1-\frac{.2c*.4c}{c^2}}##
##\lambda” = \lambda (1 + \frac{u’}{c})##
##L” = \gamma L=L \frac{1}{\sqrt{1-\frac{u’^2}{c^2}}}##
##f” = \frac{u’}{L”}##

(f) Show that the formula for the red shift can be written as

##f’=f \sqrt{\frac{1 \pm \beta}{1 \pm \beta}}##
 
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  • #2
Question (a) is strange. In the reference system of the star, there is no "ahead" and "behind" as the star does not move.

(e) is fine - get the relative speed with relativistic velocity addition, do the same calculations as before.
 
  • #3
I'd say your answer for (a) is wrong. mfb's comment should give you a hint as to why if you don't already see why. But it seems perhaps your answer is what was intended. You should ask your teacher.
 

1. What is the relativistic doppler effect for light?

The relativistic doppler effect for light is a phenomenon in which the wavelength and frequency of light are affected by the relative motion of the source and observer. This means that the observed wavelength and frequency of light can appear different depending on the relative motion between the source and observer.

2. How does the relativistic doppler effect for light differ from the classical doppler effect?

The relativistic doppler effect takes into account the effects of special relativity, such as time dilation and length contraction, which can significantly impact the observed wavelength and frequency of light. The classical doppler effect only considers the relative motion of the source and observer.

3. Can the relativistic doppler effect for light be observed in everyday life?

Yes, the relativistic doppler effect for light can be observed in everyday life. For example, the color of a star can appear slightly different depending on its relative motion with respect to the Earth. This effect is also utilized in technologies such as GPS, which must take into account the relativistic doppler effect for light in order to accurately calculate location.

4. How is the relativistic doppler effect for light calculated?

The relativistic doppler effect for light is calculated using the equation: λobs = (1 + v/c) * λsource, where λobs is the observed wavelength, v is the relative velocity between the source and observer, c is the speed of light, and λsource is the emitted wavelength of the source.

5. What is the significance of the relativistic doppler effect for light in astrophysics?

The relativistic doppler effect for light is crucial in understanding the motion and properties of objects in space. It is used to calculate the redshift or blueshift of light from distant sources, which can provide information about the expansion of the universe and the velocity of objects in space. It is also used to study the behavior of light around black holes and in other extreme environments.

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