haruspex said:
right! Hmm... However, it is hard to picture the circuit in the way you described it. I could not come up with that sketch on my own...Delta2 said:
Yes agreed from the image of the wire with the circle in the middle your mind just doesn't think the corresponding lumped model of the two resistors of 1/3 in series with the two resistors of 1/6 which are in parallel.Aristarchus_ said:
The formula for calculating the resistance of a circuit with a circular section is R = (ρ * L) / A, where R is resistance, ρ is the resistivity of the material, L is the length of the circular section, and A is the cross-sectional area of the circular section.
The diameter of a circular section directly affects the cross-sectional area of the circuit, which in turn affects the resistance. A larger diameter will result in a larger cross-sectional area and therefore a lower resistance, while a smaller diameter will result in a smaller cross-sectional area and a higher resistance.
Yes, the material of the circular section does impact the resistance of the circuit. Different materials have different resistivities, which can affect the overall resistance of the circuit. Materials with higher resistivities will result in higher resistance, while materials with lower resistivities will result in lower resistance.
The length of the circular section directly affects the resistance of the circuit. The longer the length, the higher the resistance will be. This is because resistance is directly proportional to length, meaning that as the length increases, so does the resistance.
Yes, the resistance of a circuit with a circular section can be reduced by increasing the diameter of the circular section, using a material with a lower resistivity, or shortening the length of the circular section. Additionally, using conductors with a larger cross-sectional area can also help reduce resistance.