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trap101
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I've been having this small problem with modulo arithmetic that's just irking me and this is the perfect example to get clarifivation
find the remainder for 75 congruent to x (mod 21)
here's my issue...so I'd set this up to solve and see if I could find this relationship
7[itex]\equiv[/itex] x (mod 21)...now 7 is a multiple of 21, but of course 21 doesn't divide 7 unless we take into account the negative numbers which would produce 7 [itex]\equiv[/itex] -12 (mod 21)...is this the right way to look at that?
the next thing I did and which made it easier was look at 72 [itex]\equiv[/itex] 7 (mod 21) ...now I have 75 [itex]\equiv[/itex] 7 (mod 21) when all is said and done...but the fact that I know 7 has a relationship with 21 is sitting uneasy with me...
find the remainder for 75 congruent to x (mod 21)
here's my issue...so I'd set this up to solve and see if I could find this relationship
7[itex]\equiv[/itex] x (mod 21)...now 7 is a multiple of 21, but of course 21 doesn't divide 7 unless we take into account the negative numbers which would produce 7 [itex]\equiv[/itex] -12 (mod 21)...is this the right way to look at that?
the next thing I did and which made it easier was look at 72 [itex]\equiv[/itex] 7 (mod 21) ...now I have 75 [itex]\equiv[/itex] 7 (mod 21) when all is said and done...but the fact that I know 7 has a relationship with 21 is sitting uneasy with me...
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