Stirling's Approximation for a factorial raised to a power

In summary, the conversation discusses using log identities and Stirling's Approximation to find an approximation for ##[(\alpha - 1)!]^2##. However, the proposed solution is incorrect and instead, the correct approach is to first use Stirling's Approximation to approximate ##(\alpha - 1)!## and then square that result.
  • #1
rmiller70015
110
1
Homework Statement
Find Stirling's Approximation for ##[(\alpha - 1)!]^2##
Relevant Equations
For large N: ##log(N!) \approx Nlog(N)-N##
Using log identities:
##log((\alpha - 1)!^2) = 2(log(\alpha - 1)!)##
Then apply Stirling's Approximation
##(2[(\alpha - 1)log(\alpha - 1) - (\alpha - 1)##
## = 2(\alpha -1)log(\alpha -1) - 2\alpha+2##

Is this correct? I can't find a way to check this computationally.
 
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  • #2
rmiller70015 said:
Homework Statement:: Find Stirling's Approximation for ##[(\alpha - 1)!]^2##
Relevant Equations:: For large N: ##log(N!) \approx Nlog(N)-N##

Using log identities:
##log((\alpha - 1)!^2) = 2(log(\alpha - 1)!)##
Then apply Stirling's Approximation
##(2[(\alpha - 1)log(\alpha - 1) - (\alpha - 1)##
## = 2(\alpha -1)log(\alpha -1) - 2\alpha+2##

Is this correct? I can't find a way to check this computationally.
I don't think it's correct, and I get something different. If you want to approximate ##[(\alpha - 1)!]^2##, first use Stirling's to approximate ##(\alpha - 1)!##, and then square that result.
 
Last edited:
  • #3
Thanks, that was bugging me.
 

1. What is Stirling's Approximation for a factorial raised to a power?

Stirling's Approximation is a mathematical formula used to approximate the value of a factorial raised to a power. It is often used when dealing with large numbers or in situations where an exact solution is not necessary.

2. How is Stirling's Approximation calculated?

Stirling's Approximation is calculated using the formula n! ≈ √(2πn)(n/e)^n, where n is the value of the factorial. This formula provides a close approximation to the actual value of the factorial raised to a power.

3. When is Stirling's Approximation most commonly used?

Stirling's Approximation is most commonly used in situations where a factorial raised to a power appears frequently, such as in probability and statistics problems. It is also used in physics and engineering when dealing with large numbers.

4. What are the benefits of using Stirling's Approximation?

One of the main benefits of using Stirling's Approximation is that it simplifies complex calculations involving factorials raised to a power. It also provides a close approximation to the actual value, making it a useful tool in many mathematical and scientific fields.

5. Are there any limitations to Stirling's Approximation?

Stirling's Approximation is an approximation and therefore, it is not always accurate. It is most accurate when dealing with large numbers, but as the number decreases, the accuracy also decreases. Additionally, Stirling's Approximation does not work well with negative numbers or fractions.

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