Symmetry of an exponential result from a Fourier transform

In summary, the conversation discusses the use of a matrix and FFT to calculate the Fourier transform of a lorentzian. The result is a decaying exponential followed by a mirror image of the exponential going up. The conversation also mentions the presence of an imaginary component in the FFT result and the possibility of aliasing. The main questions are why the exponential is going up in the second half and why the FFT shows an imaginary component while the matrix method does not. The conversation suggests using the Nyquist theorem and properly centering the data to avoid these issues.
  • #1
Gama
5
3
I used a matrix to calculate the Fourier transform of a lorentzian and it did generate a decaying exponential but that was followed by the mirror image of the exponential going up. I am referring to the real part of the exponential. If I use an fft instead I also see this. Shouldn't the result be just a decaying exponential? Also the fft shows an imaginary component whereas my matrix does not. I don't think there should be an imaginary component since the lorentzian is an even function centered at zero. Perhaps the fft does not treat it as centered at zero. So I have two questions, one is why is the exponential going up in the second half of the real part and why does the fft show an imaginary part that the matrix method does not show?
 
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  • #2
Gama said:
I used a matrix to calculate the Fourier transform of a lorentzian and it did generate a decaying exponential but that was followed by the mirror image of the exponential going up.
I guess that what you got at the end there is the negative-frequency components. See, e.g.,
https://dsp.stackexchange.com/questions/2818/extracting-frequencies-from-fft

Gama said:
Perhaps the fft does not treat it as centered at zero.
Exactly. It assumes that the first input element is at ##t=0##. If it is not, the result is equivalent to time shifting, which introduces a complex phase. You need to either shift back the complex phase or change the input, starting at ##t=0## and then use the periodicity implied by the Fourier transform to input at a later time the values corresponding to negative times in your case.
https://en.wikipedia.org/wiki/Fourier_transform#Translation_/_time_shifting
 
  • #3
Oh, it's a matter of aliasing. I'm not sure if you heard about Nyquist theorem and that's the key to understand the first part of your question. For a finite set of N sample points, Nyquist theorem will tell you that you have only N/2 frequency components. However, when you do FFT of N points, you get exactly N values. The first half of the data represent the frequency components at 0, 1, 2, 3, etc. multiple of the fundamental frequency (Fundamental frequency is 1/total sampling time). The other half of the data correspond to aliased negative frequency data, that is, the last data point correspond to -1 * fundamental frequency, the second last is -2 fundamental frequency, etc.
That's why you observe the data point decaying for the first half of your spectrum, but exponentially raising in the second half. It is simply the result of frequencies actually decreasing in magnitude as index of array increases.
Similar thing explains why you getting complex values. If you want FFT to give you real values only (as you expect it should be) then, the first data point should be at t = 0, the second at t = dt, third at t = 2dt, etc. The data points at t < 0 should be placed at the end of the array and reflected back in time.
Or,
simply use Matlab FFT function that automatically centers both, time and frequency domain data
 
  • #4
Henryk said:
Oh, it's a matter of aliasing.
I disagree. This does not sound like the result of aliasing.

@Gama: It would be helpful if you could post some figures of what you get.
 

1. What is the Fourier transform and how does it relate to symmetry?

The Fourier transform is a mathematical operation that decomposes a signal into its constituent frequencies. It is commonly used in signal processing and image analysis. The symmetry of an exponential result from a Fourier transform refers to the fact that the transform of a symmetric function is also symmetric.

2. Why is symmetry important in the context of a Fourier transform?

Symmetry is important in a Fourier transform because it can simplify the mathematical calculations and make the interpretation of the results easier. It also allows us to use properties of symmetry to make inferences about the original signal.

3. What are the different types of symmetry that can be observed in a Fourier transform?

There are two types of symmetry that can be observed in a Fourier transform: even symmetry and odd symmetry. Even symmetry means that the function is symmetric about the y-axis, while odd symmetry means that the function is symmetric about the origin.

4. How can the symmetry of an exponential result from a Fourier transform be determined?

The symmetry of an exponential result from a Fourier transform can be determined by analyzing the original function and its transform. If the original function is symmetric, then the transform will also be symmetric. Similarly, if the original function is odd, then the transform will be odd.

5. What are some real-world applications of understanding the symmetry of an exponential result from a Fourier transform?

Understanding the symmetry of an exponential result from a Fourier transform is important in various fields such as signal processing, image analysis, and physics. It can be used to analyze and interpret data in these fields, as well as to improve the efficiency of calculations and algorithms used in these applications.

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