The derivative of Heat Capacity with respect of pressure

In summary, the conversation discusses the writer's attempt to solve a homework problem involving an ideal gas and the use of partial derivatives to prove the derivative of heat capacity for constant pressure or volume is zero. The writer provides a hint to start with the equation for internal energy and mentions that the partial derivatives for an ideal gas are equal to certain values.
  • #1
Astrocyte
12
2
Homework Statement
Show that derivative of Heat Capacity for constant V with respect of pressure for ideal gas is "zero"
(∂C_V/∂P)_T=0
Relevant Equations
C_V=T(∂S/∂T)_V, pV=nKT
1588453059354.png

I'm thinking about that for 1 hour. But, I could not do it.
 
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  • #2
Your result for ideal gas is written as ##-p(\frac{\partial V}{\partial T})_S > 0 ##.

Not for this homework, but for slightly modified ones, i.e.,

Show that derivative of Heat Capacity for constant P with respect of pressure for ideal gas is "zero"
(∂C_P/∂P)_T=0

or

Show that derivative of Heat Capacity for constant V with respect of volume for ideal gas is "zero"
(∂C_V/∂V)_T=0

with pV=nKT, I could prove it.
 
Last edited:
  • #3
Here's a hint: Start out by writing $$dU=\left(\frac{\partial U}{\partial T}\right)_VdT+\left(\frac{\partial U}{\partial V}\right)_TdV$$What are the partial derivatives in this equation equal to for the case of an ideal gas?
 

1. What is the definition of the derivative of heat capacity with respect to pressure?

The derivative of heat capacity with respect to pressure is the rate of change of heat capacity with respect to pressure. It measures how much the heat capacity of a substance changes with a small change in pressure.

2. Why is the derivative of heat capacity with respect to pressure important?

The derivative of heat capacity with respect to pressure is important because it helps us understand how a substance responds to changes in pressure. It can also provide information about the thermodynamic properties of a substance and how it behaves under different conditions.

3. How is the derivative of heat capacity with respect to pressure calculated?

The derivative of heat capacity with respect to pressure can be calculated by taking the partial derivative of the heat capacity equation with respect to pressure. This involves holding all other variables constant and then solving for the rate of change of heat capacity with respect to pressure.

4. What factors can affect the derivative of heat capacity with respect to pressure?

The derivative of heat capacity with respect to pressure can be affected by various factors such as the type of substance, temperature, and pressure range. It may also vary depending on whether the substance is in a solid, liquid, or gas state.

5. How is the derivative of heat capacity with respect to pressure used in practical applications?

The derivative of heat capacity with respect to pressure is used in various practical applications, such as in the design of thermal systems and processes. It can also be used to determine the critical point of a substance and to predict the behavior of materials under extreme pressure conditions.

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