- #1
Fatima Hasan
- 319
- 14
- Homework Statement
- Two chambers, 10 m3 each, are interconnected by a valve, as shown in the figure, with one chamber containing air at 2500 kPa and 287°C and the other chamber is evacuated. The valve is now opened and the air reaches a mechanical equilibrium and a thermal equilibrium with the surroundings at 15°C. Determine (a) the final pressure, (b) the final temperature of air, (c) the total change in internal energy, and (d) the amount of heat transfer.
- Relevant Equations
- Here is my work :
State 1 :
A
V1A = 10 m^3
P1A = 2500 kPa
T1A = 560 K
m1A = P1A * V1A / (T1A *R)
m1A = 155.5 kg
B
V2A = 10 m^3
m2A = 0 kg
State 2 :
T = 15+273 = 288 K , and that's the final temperature ? ( not sure about that , because it's given and the question in part (b) asks to get the final temperature )
m2 = m1A + m2A
m2 = 155.5 kg
V2 = V1A + V2A
V2 = 10 + 10 --> = 20 m^3
P2 = m2 * R * T / V2
P2 = 642.6504 K Pa ( the final pressure )
Since there are no heat and work interactions ,
c) = 0
d) = 0
Could someone check my answer please ?