Uncertainty of energy in a quantum harmonic oscillator

In summary, the uncertainty of the kinetic energy of a quantum harmonic oscillator in the ground state can be found using the equations \left\langle p^2_x \right\rangle = \displaystyle\frac{\hbar^2}{2a^2} and \left\langle p^4_x \right\rangle = \displaystyle\frac{3\hbar^2}{4a^2}. The equation \Delta E_{kin}=\sqrt{\left\langle E^2_{kin} \right\rangle - \left\langle E_{kin} \right\rangle^2} can then be used to calculate the uncertainty. Additionally, \left\langle E_{kin} \right\rangle = \
  • #1
bobred
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Homework Statement


Find the uncertainty of the kinetic energy of a quantum harmonic oscillator in the ground state, using

[itex]\left\langle p^2_x \right\rangle = \displaystyle\frac{\hbar^2}{2a^2}[/itex] and
[itex]\left\langle p^4_x \right\rangle = \displaystyle\frac{3\hbar^2}{4a^2}[/itex]


Homework Equations


[itex]\Delta E_{kin}=\sqrt{\left\langle E^2_{kin} \right\rangle - \left\langle E_{kin} \right\rangle^2} [/itex]

[itex]\left\langle E_{kin} \right\rangle = \displaystyle\frac{\left\langle p^2_x \right\rangle}{2m} [/itex]

The Attempt at a Solution


With [itex]\left\langle E_{kin} \right\rangle^2[/itex] I have no problem with but am I valid in saying

[itex]\left\langle E^2_{kin} \right\rangle = \displaystyle\frac{\left\langle p^4_x \right\rangle}{4m^2}[/itex]?
 
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  • #2
bobred said:
am I valid in saying

[itex]\left\langle E^2_{kin} \right\rangle = \displaystyle\frac{\left\langle p^4_x \right\rangle}{4m^2}[/itex]?
Yes.
 

Related to Uncertainty of energy in a quantum harmonic oscillator

What is uncertainty of energy in a quantum harmonic oscillator?

The uncertainty of energy in a quantum harmonic oscillator refers to the inherent unpredictability of the energy states of a particle within the oscillator. This arises from the principles of quantum mechanics, which state that it is impossible to know both the position and momentum of a particle with absolute certainty. As a result, there is always a degree of uncertainty in the energy of a quantum harmonic oscillator.

How is uncertainty of energy calculated in a quantum harmonic oscillator?

Uncertainty of energy in a quantum harmonic oscillator is calculated using the Heisenberg uncertainty principle, which states that the product of the uncertainties in position and momentum must be greater than or equal to Planck's constant divided by 4π. This can be represented mathematically as ∆E∆t ≥ h/4π, where ∆E is the uncertainty in energy and ∆t is the uncertainty in time.

Why is uncertainty of energy important in quantum mechanics?

Uncertainty of energy is a fundamental concept in quantum mechanics and is important because it places limits on our ability to observe and measure the properties of particles at the subatomic level. It also has practical applications, such as in the development of technologies like quantum computing and cryptography.

How does uncertainty of energy affect the behavior of a quantum harmonic oscillator?

The uncertainty of energy in a quantum harmonic oscillator leads to the probabilistic nature of its energy states. This means that the particle can exist in a range of energy states rather than a single, definite energy state. As a result, the behavior of the oscillator is characterized by fluctuations and is not completely predictable.

Can uncertainty of energy be reduced or eliminated in a quantum harmonic oscillator?

No, uncertainty of energy cannot be reduced or eliminated in a quantum harmonic oscillator. This is a fundamental principle of quantum mechanics and is not a limitation of our measurement techniques. However, by carefully manipulating and controlling the system, we can minimize the uncertainty and make more accurate predictions about the behavior of the oscillator.

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