- #1
louza8
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Homework Statement
http://img713.imageshack.us/img713/9151/screenshot20110501at113.png
Homework Equations
Angular acceleration = Torque/Inertia
Torque = Fd
Mass_moment_Inertia=mr^2
The Attempt at a Solution
->assume masses on the end of seesaw are point particles for calculating inertia. is this the correct thing to do?
->is this formula for angular acceleration fine for the instant at release?
I=mr^2
I=m[d-a]^2-ma^2
I=m[(d-a)^2 - a^2]
Torque = Fd
Torque = mg[(d-a)-a]
Angular acceleration= Torque/Inertia
[(d-a)-a]mg/[(d-a)^2 - a^2]m ---->cancel m from top and bottom
=g/(d-2a) ---->canceled (d-a)-a from the top and bottom (because equivalent to rg/r^2)
I think my maths at the end might be dodgy, maybe my assumptions are incorrect too.
Thanks in advance for your help!
Edit: Or should I somehow be using the equations of motion for this one? I can't see how though :'(
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