Verifying Divergence Theorem on Sphere with F(x,y,z)=zi+yj+xk

In summary, the conversation is about verifying the divergence theorem for a given solid sphere and function. The attempt at a solution involves finding the volume of the sphere using a triple integral and then using the surface integral formula to calculate the total flux. The suggestion is to split the sphere in half and evaluate the surface integral for one half before multiplying by 2 to get the total flux.
  • #1
bugatti79
794
1

Homework Statement



Folks,

Verify the divergence theorem for

F(x,y,z)=zi+yj+xk and G the solid sphere x^2+y^2+z^2<=16

Homework Equations



##\int\int\int div(F)dV##

The Attempt at a Solution



My attempt

The radius of the sphere is 4 and div F= 1, therefore the integral becomes

##\int\int\int div(F)dV=\int_0^{2\pi} \int_0^{\pi} \int_0^{4} 1dV=\int_0^{2\pi} \int_0^{\pi} \int_0^{4} 2\rho^2 sin (\phi) d\rho d\phi d \theta##

Is this correct so far?
Thanks
 
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  • #2
where did the 2 come from in the integrand? Other than that it's right.

EDIT: Also, since divF is a constant and the volume of a sphere can easily be found, you don't actually need to evaluate an integral.
 
  • #3
cjc0117 said:
where did the 2 come from in the integrand? Other than that it's right.

EDIT: Also, since divF is a constant and the volume of a sphere can easily be found, you don't actually need to evaluate an integral.

Hi, that should be a 1, ie

##...=\int_0^{2\pi} \int_0^{\pi} \int_0^{4} \rho^2 sin (\phi) d\rho d\phi d \theta##
But it says I need to verify the Divergence Theorem...so I guess I can continue and verify?

Thanks
 
  • #4
[itex]\int_0^{2\pi} \int_0^{\pi} \int_0^{4} dV[/itex] = volume of sphere with radius 4.

Just use the well-known formula for calculating volume of sphere. The answer should obviously be the same as the evaluation of your triple integral expression above.

Now, when you're asked to verify the Gauss Divergence Theorem, you should independently calculate the total flux using the surface integral formula, to confirm your answer.
[tex]\iint_S \vec F \hat n \,.d\sigma[/tex]
Hint: To make it easier, split the sphere exactly in half laterally and evaluate the surface integral for one half. Then multiply by 2 to get the total flux.
 
Last edited:
  • #5
sharks said:
[itex]\int_0^{2\pi} \int_0^{\pi} \int_0^{4} dV[/itex] = volume of sphere with radius 4.

Just use the well-known formula for calculating volume of sphere. The answer should obviously be the same as the evaluation of your triple integral expression above.

Now, when you're asked to verify the Gauss Divergence Theorem, you should independently calculate the total flux using the surface integral formula, to confirm your answer.
[tex]\iint_S \vec F \hat n \,.d\sigma[/tex]
Hint: To make it easier, split the sphere exactly in half laterally and evaluate the surface integral for one half. Then multiply by 2 to get the total flux.

Ok, thanks guys. Will respond hopefully at some stage.

Cheers
 
  • #6
Note: [itex]d\sigma[/itex] is the differential area.
 

1. What is the Divergence Theorem?

The Divergence Theorem is a mathematical theorem that relates a surface integral over a closed surface to a volume integral over the region enclosed by the surface. It is also known as Gauss's Theorem or Ostrogradsky's Theorem.

2. How is the Divergence Theorem used to verify a surface integral on a sphere?

To verify a surface integral on a sphere, the Divergence Theorem is used to convert the surface integral into a volume integral. The sphere is treated as a closed surface, and the function F(x,y,z) is used as the divergence of a vector field. The resulting volume integral is then evaluated to verify the original surface integral.

3. What is the formula for the Divergence Theorem?

The formula for the Divergence Theorem is: ∫∫S F(x,y,z) · dS = ∭V ∇ · F(x,y,z) dV, where F(x,y,z) is a vector field, S is a closed surface, and V is the region enclosed by the surface.

4. What is the significance of using a sphere in the verification of the Divergence Theorem?

The sphere is a common shape used in the verification of the Divergence Theorem because it is a simple and symmetric shape. This allows for easier calculations and makes it a good choice for demonstrating the application of the theorem.

5. What are some real-life applications of the Divergence Theorem?

The Divergence Theorem has a wide range of applications in physics and engineering, including fluid mechanics, electromagnetism, and heat transfer. For example, it is used to calculate the flow of a fluid through a closed surface or to determine the electric flux through a closed surface surrounding a point charge.

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