SteamKing said:If the normal force is greater than the weight of the box, the box will want to travel upward, F = ma and all that.
These types of problems are best analyzed by drawing free body diagrams of the boxes and applying the known forces to them. Once that is accomplished, the equations of equilibrium can be written and solved.
tristanmagnum said:so would the normal force being exerted be 98.0N?
The normal force is a contact force that acts perpendicular to the surface of an object. It is a reaction force that occurs whenever an object is in contact with a surface.
The normal force is equal in magnitude but opposite in direction to the force exerted by an object on a surface. It can be calculated using the formula N = mg cos(theta), where N is the normal force, m is the mass of the object, g is the acceleration due to gravity, and theta is the angle between the object and the surface.
The normal force and weight are equal in magnitude when an object is at rest or moving with a constant velocity on a horizontal surface. However, when an object is on an inclined plane, the normal force is less than the weight of the object due to the angle of the surface.
The normal force plays a crucial role in determining the motion of an object. It helps balance out other forces acting on the object, such as gravity and friction, and ensures that the object remains in contact with a surface.
No, the normal force can never be negative. It always acts in a direction perpendicular to the surface and is always equal to or greater than zero. If an object is on a tilted surface, the normal force may be less than the weight of the object, but it will never be negative.