Why is fluorine more electronegative than sodium?

In summary, the trends in electronegativity can be explained by the increase in nuclear charge and electrons in the outermost shell. This leads to a stronger effective nuclear charge and tighter binding of electrons, resulting in higher electronegativity. This is the basis for the Allred-Rochow electronegativity scale, which correlates with the Pauli scale.
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I've learned the trends in electronegativity, but why is fluorine more electronegative than sodium? What is the real reasoning behind it?
 
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When going from sodium to fluorine, both the nuclear charge and the electrons in the outmost shell (i.e. electrons with approximately the same distance from the nucleus on average) increases. These electrons in the same shell are not very efficient in screening each other from the nuclear charge as about 50% of the electrons are farther outside than a given electron under consideration (See Slater's rules: http://en.wikipedia.org/wiki/Slater's_rules). Hence the effective nuclear charge seen by the outmost electrons increases continuously and the electrons become more tightly bound leading to increased electronegativity.
This physical argument forms the basis for the definition of the Allred-Rochow electronegativity scale which correlates well with the Pauli scale:
http://en.wikipedia.org/wiki/Electronegativity
 

Related to Why is fluorine more electronegative than sodium?

1. Why is fluorine more electronegative than sodium?

Fluorine is more electronegative than sodium because it has a higher number of protons in its nucleus, which creates a stronger pull on the electrons in its outermost energy level. This results in fluorine having a greater ability to attract and hold electrons compared to sodium.

2. What factors contribute to fluorine's high electronegativity?

Besides having a higher number of protons, fluorine also has a smaller atomic radius and a higher effective nuclear charge, meaning that the electrons are held more tightly by the nucleus. Additionally, fluorine has one less energy level compared to sodium, making it easier for the nucleus to attract and hold onto electrons.

3. How does electronegativity affect chemical reactions?

Electronegativity plays a significant role in determining the type of bond that will form between atoms. In the case of fluorine and sodium, fluorine's high electronegativity causes it to attract electrons from sodium, leading to the formation of an ionic bond. Electronegativity also affects the polarity of molecules and their reactivity in chemical reactions.

4. Can electronegativity change within the same element?

Electronegativity is a periodic trend and generally increases from left to right across the periodic table. It can also vary within the same element depending on its oxidation state. For example, in the case of sodium, its electronegativity is lower in its ionic form (Na+) compared to its metallic form (Na), where it is more similar to fluorine.

5. How does fluorine's electronegativity impact its reactivity?

Fluorine's high electronegativity makes it a highly reactive element, as it seeks to gain an electron to achieve a stable octet in its outer energy level. This makes it a strong oxidizing agent and allows it to form compounds with almost all other elements in the periodic table, making it one of the most reactive elements.

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