Recent content by Abarak

God, that was terrible. I'm going to stop right now and start again tomorrow. Sorry for the waste of time.

Let me try this again... W = (85.0N)(3cm+5cm)*1 W = 680J (3cm + 5cm) because the block is moving from -3cm to 0 and from 0 to 5cm. This gives us a grand total of 8cm the block was moved. Sorry for the rather rudimentary question.

Homework Statement Find the work W done on the block by the force of magnitude F = 85.0N as the block moves from xi = -3.00cm to xf = 5.00cm. Homework Equations W = F*S*cos(theta) The Attempt at a Solution W = (85.0N)(-3cm-5cm)*1 W = -260J Am I missing something?

Never mind, I calculated the last equation wrong. Thanks anyways! -- Abarak

Homework Statement A glass flask whose volume is 1000cm^{3} at a temperature of 0.00*10^0 Celsius is completely filled with mercury at the same temperature. When the flask and mercury are warmed together to a temperature of 52 Celsius, a volume of 8.35cm^{3} of mercury overflows the flask...

Hey Dick, Thanks for the help. I was able to get the correct answer. Man, I could never do what you Homework Helper's do but it REALLY helps! I am taking an online physics class right now and not having someone to talk to really sucks. If I need to ask my professor a question it takes days...

Question A 54.0kg ice skater spins about a vertical axis through her body with her arms horizontally outstretched, making 2.50 turns each second. The distance from one hand to the other is 1.5m. Biometric measurements indicate that each hand typically makes up about 1.25% of body weight...

Oh snap! Talk about a lack of judgment. After applying Newton's 2nd Law everything worked like a charm. Thanks again for the help Doc. -- Abarak

From what I gather the object is not accelerating so Newton's 2nd law would not apply to this. "force a spring exerts is proportional to the distance it is stretched or compressed with respect to its equilibrium length" I don't see how this would apply to Newton's second law or the other...

Thanks for the help. I keep over thinking these problems and I need to stop. -- Abarak

Homework Statement On October 15, 2001, a planet was discovered orbiting around the star HD68988. Its orbital distance was measured to be 10.5 million kilometers from the center of the star, and its orbital period was estimated at 6.3 days. Question A: What is the mass of HD68988? -- I...

Homework Statement An object of mass M = 3.00 kg is attached to a spring with spring constant k = 132 N/m whose unstretched length is L = 0.170 m, and whose far end is fixed to a shaft that is rotating with an angular speed of omega = 2.00 radians/s. Neglect gravity and assume that the mass...

Hey Doc, DH and Chi! I was able to solve every part with your help. Thank you very much for taking your time with me. -- Abarak

Hey Doc Al, Ok, this is what I did and I still got the wrong answer real weight = 724N = m*g 724N = m * 9.8 m/s^2 m = 73.878kg Because the seat needs to support the weight of the person I used F = m * (\frac{v^2}{r}) F = 73.878 * (\frac{5.24^2}{50}) = 40.57N normal force + real...

Yeah, I tend to do that from time to time. Let me just make sure I understand this correctly. The passengers normal weight is 724 N At the top of the Ferris Wheel all I need to do is add the normal weight to the gravitation weight. 724N+(-9.8m/s^2) = 714.2N?? What about when the...