Thermal Dynamics Homework: Calculate \Delta V_{Hg}

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SUMMARY

The discussion centers on calculating the change in volume of mercury (\Delta V_{Hg}) when heated from 0.00°C to 52°C in a 1000 cm³ flask. The coefficient of volume expansion for mercury is given as \beta_{Hg} = 1.80 \times 10^{-4} K^{-1}. The correct calculation for the change in temperature (\Delta T) is 52 K, leading to a calculated change in volume of \Delta V_{Hg} = 7.8 cm³. The user initially miscalculated the final equation but later acknowledged the error.

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Abarak
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Homework Statement



A glass flask whose volume is [tex]1000cm^{3}[/tex] at a temperature of [tex]0.00*10^0[/tex] Celsius is completely filled with mercury at the same temperature. When the flask and mercury are warmed together to a temperature of 52 Celsius, a volume of [tex]8.35cm^{3}[/tex] of mercury overflows the flask.

the coefficient of volume expansion of mercury is [tex]\beta_{Hg} = 1.80*10^{-4}[/tex]K

Problem:
Calculate the change in volume of the mercury [tex]\Delta V_{Hg}[/tex] during heating.

Homework Equations



[tex]\Delta T = T_f - T_i[/tex]
[tex]\Delta V = \beta V_o \Delta T[/tex]

The Attempt at a Solution



[tex]\Delta T = 325.15K - 273.15K[/tex]
[tex]\Delta T = 52K[/tex]

[tex]\Delta V_{Hg} = (1.80*10^{-4})(1000)(52)[/tex]
[tex]\Delta V_{Hg} = 7.8 cm^3[/tex]

I think I am doing this right but the program keeps saying it's wrong.

Any ideas?

-- Abarak
 
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Never mind, I calculated the last equation wrong.

Thanks anyways!

-- Abarak
 

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