Thermal Dynamics Homework: Calculate \Delta V_{Hg}

AI Thread Summary
The problem involves calculating the change in volume of mercury when heated from 0°C to 52°C in a 1000 cm³ flask. The coefficient of volume expansion for mercury is given as β_Hg = 1.80*10^{-4} K. The temperature change (ΔT) is calculated as 52 K. The initial calculation for the change in volume (ΔV_Hg) was found to be 7.8 cm³, but the user later realized an error in the final equation. The discussion highlights the importance of careful calculation in thermal dynamics problems.
Abarak
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Homework Statement



A glass flask whose volume is 1000cm^{3} at a temperature of 0.00*10^0 Celsius is completely filled with mercury at the same temperature. When the flask and mercury are warmed together to a temperature of 52 Celsius, a volume of 8.35cm^{3} of mercury overflows the flask.

the coefficient of volume expansion of mercury is \beta_{Hg} = 1.80*10^{-4}K

Problem:
Calculate the change in volume of the mercury \Delta V_{Hg} during heating.

Homework Equations



\Delta T = T_f - T_i
\Delta V = \beta V_o \Delta T

The Attempt at a Solution



\Delta T = 325.15K - 273.15K
\Delta T = 52K

\Delta V_{Hg} = (1.80*10^{-4})(1000)(52)
\Delta V_{Hg} = 7.8 cm^3

I think I am doing this right but the program keeps saying it's wrong.

Any ideas?

-- Abarak
 
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Never mind, I calculated the last equation wrong.

Thanks anyways!

-- Abarak
 
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