Recent content by abilolado

Perhaps I'm misunderstanding the meaning of a solenoid. The whole point is to have the projectile, or whatever it is, being accelerated due to the magnetic field produced by the current in a looped wire. The current would be cut off once the projectile reached the middle of the coil so that...

Everything is arbitrary for now.

Hello all. Me and some friends are building a coil cannon, and we've been doing some calculations [I know its unecessary but... well, we're physicists! (well, physics students...)]. But we got stuck. How to calculate the force acting on a steel bar (or some other ferromagnetic material, maybe...

Hello all, disclaimer here, I haven't taken quantum mechanics yet, all I know of it comes form books and PBS Space Time Series. Since a photon can, at any given instant, "split" into an Electron-Positron pair, does it mean that if this occurs between point a and b, the measured speed o that...

Well, I don't know what topic you're referring to, but I'd always suggest Jackson's book on Electromagnetism. This with Misner's Gravitation (for grad school) are the two "bibles" of physics I rely mostly on.

Definitely "The Oxford Solid State Basics", by Steven H. Simon. Amazing book, explains it all very well and, best of all, the author has free lectures online where he goes over the book : Definitely recommend it, had a great time learning from it.

I think the problem is just the math in the end. Everything is right up to: \frac{450^2}{4}\text{=130$\Delta $T+25000} but \frac{450^2}{4}=50625, not 67500 as you put in your solution. So then: \text{$\Delta $T=}\frac{(50625-25000)}{130}\text{=197.115} So T=600-197.115=402.885K

You're right! My bad. Damn, all that calculus for nothing and now I realize Csc(θ) \sqrt{\frac{14}{5g}}(\sqrt{h}) \frac{s}{h}\sqrt{\frac{14}{5g}}(\sqrt{h}) s\sqrt{\frac{14}{5gh}} 2s\sqrt{\frac{14}{20gh}} 2s\sqrt{\frac{7}{10gh}} \frac{2s}{\sqrt{\frac{10gh}{7}}} Exact same thing... damn... Well...

Unfortunately I don't think doing like that works, since v is the total speed, not just the speed in the y direction, so it won't work by just plugging in the formula, since the formula only works for one dimension at a time. Also, it's got to be dependent on the angle of the ramp, since going...

If there's no loss of energy due to rebounding or anything else, then yes, you are correct on both.

Yes, you can answer it, but I guess you'd need calculus... If you don't know calculus just skip to the "which gives us:" part in the end. This is how I went through it: Through conservation of energy we know that: Pe = KE_T + KE_R At every point, so: mgh = \frac{mv^2}{2} + \frac{Iω^2}{2}...

Well, to fully understand the "why"s and "how"s, I believe you'd have to be a theoretical physicist. But I did read a book that gave me some good first insights into it, so I guess it can help you. The book is: "The Elegant Universe" by Brian Greene. But before you read that, if you'd like to...

Welcome! And Good Luck! Ps: Advise from another undergrad --> Kiss ass of the most badass professors.

Hello all. I had a few questions about obtaining a PhD in UK and/or Europe. I am currently an Undergrad physics student from Brazil studying in the US, once I am done I will pursue my PhD in some other university, since my current one, unfortunally, does not have a Physics Grad program. My dream...

I'm still an undergrad in physics and this is all becoming a bit too advanced for me. Not that I'm giving up on it, solving the wave equations for a membrane is surely a start and I might jump to the plates once I fully understand the simpler concepts. I appreciate all the help from all of you...