Recent content by aleksxxx

Awesome, basically what i thought. This would be the case becuase the displacement is off an angle from the direction of mg, correct?

Ok cool - that makes sense. But to me it seems for most questions - i.e: "how much work is done by the applied force moving a box of mass M a distance of D" you would get a non-zero answer, but if the question actually specified "How much work is done by gravity..." then you would get zero...

Okay - This isn't really a homework problem, but i had a question about the work equation, W=Fdcos(theta) Say, for example, you have a block sitting on a surface and there is friction, but we are not talking it into account. There is a force of 10N applied parallel to the displacement...

any ideas, anyone?

Homework Statement Assume the field inside the larger coil (.075m Radius, 1200 loops), reaches the maximum value when the smaller solenoid, (.05m radius, 1200 loops), is halfway inserted. with what constant velocity must the smaller solenoid be inserted to induce 2.3V in the larger solenoid...

I worked on the loop equations more and found I1, I2, and I3 in terms of I. I then substituted those into the I1+I2+I3=I equation getting a current (I) of .041 A leading to a deltaV of 8.1V. Does this sound right? The Current was .137A when connected in series and the deltaV of the 200 ohm...

i tried that and i seem to just keep proving that I2=I2, I1=I1, etc...

Homework Statement Find the current flowing through the 200ohm resistor E1=5v E2=10v E3=15v r1=3ohms r2=6ohms r3=9ohmsThe Attempt at a Solution I know that I1+I2+I3=I I can't seem to get a loop rule that will allow me to solve for I though. I came up with the equivalent resistance in the...

the other way i tried the problem was like this: using the equation: E=IR I took the EMF of the first battery, 5v, and set the equation as follows: 5V=(.137A)(r1) ==> where r1=bE1 5V=(.137A)(5V)(b) b=7.3 Using that value in the second part of the problem still gives me a voltage...

There wouldn't be an EMF in that part of the equation for that, would there? I thought the loop rule was, in the direction of the loop is you hit a battery - then + terminal, its positive that EMF, and when you go through a resistor if the loop and current are the same direction its -IR...

i used the loop rule and started at E1 and went clockwise to get the first equation. Then i just plugged in the values of the batteries and the resistors to solve it. I still cannont figure out what I am doing wrong becuase the voltage I am getting is way out of whack.

Homework Statement 1. "lets set the internal resistance, r^_i, of the battery with emf E^_i equal to bE^_i where b is a constant assumed the same for all three batteries. E^_1=5v E^_2=10v E^_3=15v r1=bE^_1 r2=bE^_2 r3=bE^_3 http://i17.photobucket.com/albums/b51/chs2004/physics1.jpg 2.To...

that program is pretty neat! thanks..

i just downloaded it and am playing with it, i can't get it to work right though; what did you type into the screen.. (if you don't still have it, don't worry about it ill figure it out.)

whats that? a program??