Recent content by amy098yay

Does 90 degrees give maximum torque for 2. ?

I was given this info r=1.5 m d=3 m F= 50 N angle= 110 degrees 1. What torque is applied? T=Fsin T= (1.5)(50)sin(110) T=70 N m 2. At what angle would enough force be applied to achieve maximum toque? T=Fsin T= (1.5)(50)sin(10) T=13.0 N m 3. If someone continues to push with a force of 50 N...

heres the diagram

I was given this info r=1.5 m d=3 m F= 50 N angle= 110 degrees 1. What torque is applied? T=Fsin T= (1.5)(50)sin(110) T=70 J 2. At what angle would enough force be applied to achieve maximum toque? T=Fsin T= (1.5)(50)sin(90) T=75 (joules) 3. If someone continues to push with a force of 50 N...

90? T=Fsin T= (1.5)(50)sin(90) T=75 (joules)

would it be 180-110=10 degrees so T=Fsin T= (1.5)(50)sin(10) T=13.0 J (joules) ?

thank you for notifying me about the units being used in this problem, so how would i go about getting MAXIMUM TORQUE?

Homework Statement 2. Homework Equations [/B] I was given this info r=1.5 m d=3 m F= 50 N angle= 110 degreesThe Attempt at a Solution T=Fsin T= (1.5)(50)sin(110) T=70 J (joules) I attempted the solution^ to get (maximum) torque.

i am unsure if my answer is correct or not*

Homework Statement 2. Homework Equations [/B] I was given this info r=1.5 m d=3 m F= 50 angle= 110 degreesThe Attempt at a Solution T=Fsin T= (1.5)(50)sin(110) T=70 N I attempted the solution^ to get (maximum) torque.

alright thanks

Mod note: Member warned about posting with no effort. 1. Homework Statement Expand to the general case to explore how the cross product behaves under scalar multiplication k (a x b) = (ka) x b = a x (kb). The Attempt at a Solution would this be the right general case to portray the situation?

for sure, thank you so much for taking time out of your day to help me with this problem :)

Homework Statement Use three specific vectors in 3 space to show that ⃗ a ×(b⃗ ×c⃗ ) ≠ (a⃗ ×b⃗ )×c⃗ solution is in pdf... Homework EquationsThe Attempt at a Solution

another pdf file of the solution