Recent content by Animuo

Homework Statement Prove by Contradiction: For all integers x greater than 11, x equals the sum of two composite numbers. Homework Equations A composite number is any number that isn't prime To prove by contradiction implies that if you use a statement's as a negation, a contradiction...

You could theoretically use any conductive surface, as the amplifier inside the EEG will transform the waveform into something recognizable by us. However, if you have to ask us, I think you should read up a little bit more on EEG's before putting the time and money into building one.

Homework Statement Prove by Contradiction: For all Prime Numbers a, b, and c, a^2 + b^2 =/= c^2 Homework Equations Prime number is a number whose only factors are one and itself. Proof by contradiction means that you take a statement's negation as a starting point, and find a...

Yeah I'm just getting to it now actually, but problem I mentioned is prior to the discussion of mod and div in the book. I suppose it expects me to just spell out what happens when one is subtracted from any number 10 ^ m could produce, but I thought there would be a general more axiomatic truth...

Wow... didn't think of that, I used the google calculator and now I feel like a dumbass -.-. Thanks guys, feel better now. Here's another one I'm having a little difficulty with, and I don't feel like spamming these forums. Moderator note: I made a separate thread for the new problem.[/color]

Wow... didn't think of that, I used the google calculator and now I feel like a dumbass -.-. Thanks guys, feel better now. Here's another one I'm having a little difficulty with, and I don't feel like spamming these forums. Basically the part I'm having difficulty with is a portion of a larger...

Did you copy this question verbatim from what a teacher said/wrote on the board or do you actually have the physical question in front of you?

Homework Statement How many zeroes are at the end of (45^8)(88^5), don't use a calculator. Homework Equations Using the unique factorization of integers theorem, you can break any integer down into the product of prime integers. The Attempt at a Solution So I broke it down (45^8) = (3 *...

Thanks guys, I already figured out the solution but some of you guys employ some interesting methodology.. I'll give it a look when I have more time and see what I think.

Uggh I am literally soo bad at factoring.. which is why I kinda handed the reins over.. anyways by trial and error, and some common-sense I came up with (n^2 + 3n + 1)^2 = k^2, so that proves the four consecutive numbers produce a perfect square minus one. I had a lot of trouble factoring this...

Homework Statement The product of any 4 consecutive integers will be one less than a perfect square. Homework Equations Well, a perfect square is a number that can be broken down to n*n where n is an integer. If a number is consecutive to another number that means it is exactly one more...

Aha, can't believe I missed such an easy solution, guess it's good to humble one down, thanks for the help mates... I'm new to this forum is there anything like +rep or likes that I can give?

Homework Statement Well, the problem is a discrete math problem to prove that the difference of an even integer and an odd integer is an odd integer. Homework Equations If you let m = an even integer, and n = an odd integer then m = 2r for some integer r, while n = 2s + 1 for some integer...