Recent content by AshesToFeonix

wow awesome thanks that clears up a lot. I almost gave up on anyone answering me. I read that there was a way to close a thread or say that the problem is solved but I'm not seeing it on here so I guess'll have to leave it as is.

Homework Statement 6. A particle of mass m moves along a frictionless, horizontal plane with a speed given by v(x) = α / x. Where x is the distance of the object from the origin and α is a constant. Working with F = ma, we want to get the acceleration. You have v = v(x). You...

...well that's order of operations. you will have serious trouble passing without knowing them... .58m = 0 + 0 + .5 (9.81m/s^2)(t^2) to get t by itself 1) add or subtract from each side (in this case that part is 0) 2) multiply or divide 3) take your square root t^2 = the sq root...

remember velocity is a vector too and can be treated like distances. Draw a triangle to represent the x and y velocities. if you set it up right you should be able to use the Tan funtion to find the y velocity component. I'm sure you can figure it out from there

this is ticky as far as component problems go... I know nothin about a range formula, I'll assume its a variation of the basics... 1) okay first you break down the ball's velocity into components. that means Vx = Vcos(38.6) and Vy = Vsin(38.6) 2) next we want to know how long this ball...

...well in that case I don't think u need help at all, because I got the same answer! good job!

well you did the hard part... I would've found the velocity first then broken it down into components, but I suppose your way is just as good... you got t = .03 s you got Ax = 146.28 and Ay = 176.19 well, Velocity = (acceleration) X (time) so find Vx and Vy

Total time (hang time) = time going up + time coming down. and, time up = time down so, 2 X time down = hang time. for time down use the formula (yes V initial = 0, A = -9.81) X final = X initial + V initial (t) + 1/2A(t^2)

the formulas you need are: V final = V initial + A(t) and X final = X initial + V initial (t) + 1/2A(t^2) where x is distance, v is velocity and a is acceleration (yes, 9.81 m/s^2) write'em down, I'm sure they're in your book, and should get you started on all your problems.

r/t is average velocity. your trying to find the instaneous rate of change. which means its time to put that calc 1 to use!

This question didnt make a lot of sense to me... I don't see how it can be solved numerically. The total distance the grenade needs to travel, X final = 15.6 + 37t to find the velocity, you need the total distance, to get the the total distance you need to know the time it took for the...