Homework Statement
I took pictures of the problem with my camera, along with my solution. I couldn't get the picture to show on here, so I uploaded them to my myspace. please look at the pics in the links!
the problem...
wow awesome thanks that clears up a lot. I almost gave up on anyone answering me. I read that there was a way to close a thread or say that the problem is solved but I'm not seeing it on here so I guess'll have to leave it as is.
Homework Statement
6. A particle of mass m moves along a frictionless, horizontal plane with a speed given by
v(x) = α / x. Where x is the distance of the object from the origin and α is a constant.
Working with F = ma, we want to get the acceleration. You have v = v(x). You...
...well that's order of operations. you will have serious trouble passing without knowing them...
.58m = 0 + 0 + .5 (9.81m/s^2)(t^2)
to get t by itself
1) add or subtract from each side (in this case that part is 0)
2) multiply or divide
3) take your square root
t^2 = the sq root...
remember velocity is a vector too and can be treated like distances. Draw a triangle to represent the x and y velocities. if you set it up right you should be able to use the Tan funtion to find the y velocity component. I'm sure you can figure it out from there
this is ticky as far as component problems go...
I know nothin about a range formula, I'll assume its a variation of the basics...
1) okay first you break down the ball's velocity into components.
that means Vx = Vcos(38.6) and Vy = Vsin(38.6)
2) next we want to know how long this ball...
well you did the hard part...
I would've found the velocity first then broken it down into components, but I suppose your way is just as good...
you got t = .03 s
you got Ax = 146.28 and Ay = 176.19
well, Velocity = (acceleration) X (time)
so find Vx and Vy
Total time (hang time) = time going up + time coming down.
and, time up = time down
so, 2 X time down = hang time.
for time down use the formula (yes V initial = 0, A = -9.81)
X final = X initial + V initial (t) + 1/2A(t^2)
the formulas you need are:
V final = V initial + A(t)
and
X final = X initial + V initial (t) + 1/2A(t^2)
where x is distance, v is velocity and a is acceleration (yes, 9.81 m/s^2)
write'em down, I'm sure they're in your book, and should get you started on all your problems.
This question didnt make a lot of sense to me... I don't see how it can be solved numerically. The total distance the grenade needs to travel, X final = 15.6 + 37t
to find the velocity, you need the total distance, to get the the total distance you need to know the time it took for the...