Recent content by astrocytosis

  1. astrocytosis

    Magnetic field of a rotating cylinder with permanent polarization

    Thank you, I think I understand now; my mistake was I mixed up the r in Biot-Savart with the s in cylindrical coordinates for a complete solution using Ampere’s law it must be assumed that B is zero outside (no fringing fields)
  2. astrocytosis

    Magnetic field of a rotating cylinder with permanent polarization

    Would this be a valid solution using Ampere’s law? Seems much simpler to do it this way... also, I miscalculated the direction of the surface current before; I now see how it can contribute to the B field inside the cylinder
  3. astrocytosis

    Magnetic field of a rotating cylinder with permanent polarization

    I am struggling to get my work to match the posted solutions to this problem. I understand part (a) but can’t get the integral to work out for (b). I know I have to use Biot-Savart and add up the components from the the surface and volume currents. The cylinder is very long, so I need to make a...
  4. astrocytosis

    Volume integral over a gradient (quantum mechanics)

    OK, I think all I need for (2) is the product rule since f*g is going to zero, but I'm still not sure how this relates to (3)
  5. astrocytosis

    Volume integral over a gradient (quantum mechanics)

    Homework Statement 1) Calculate the density of states for a free particle in a three dimensional box of linear size L. 2) Show that ##\int f \nabla g \, d^3 x=-\int g \nabla f \, d^3 x## provided that ##lim_{r \rightarrow \inf} [f(x)g(x)]=0## 3) Calculate the integral ##\int...
  6. astrocytosis

    Darwin term in a hydrogen atom - evaluating expectation values

    Homework Statement Homework Equations VD= -1/(8m2c2) [pi,[pi,Vc(r)]] VC(r) = -Ze2/r Energy shift Δ = <nlm|VD|nlm> The Attempt at a Solution I can't figure out how to evaluate the expectation values that result from the Δ equation. When I do out the commutator, I get p2V-2pVp+Vp2. This...
  7. astrocytosis

    Prove formula for the product of two exponential operators

    I thought an analytic function of an operator returned a function of its eigenvalue so it wouldn't matter... but then how can I write it in terms of T(S)?
  8. astrocytosis

    Prove formula for the product of two exponential operators

    Homework Statement Consider two operators A and B, such that [A,[A, B]] = 0 and [B,[A, B]] = 0 . Show that Exp(A+B) = Exp(A)Exp(B)Exp(-1/2 [A,B]) Hint: define Exp(As)Exp(Bs) as T(s), where s is a real parameter, differentiate T(s) with respect to s, and express the result in terms of T(s)...
  9. astrocytosis

    Induced current in a loop of wire when straight wire is cut

    Faraday's law states that EMF is the negative of the time derivative of the magnetic flux. I can find the flux for the case where there is current flowing through the wire: $$\Phi = \frac{ \mu_{0} I}{2\pi} \int_{s}^{s+a} \frac{a dr}{r} = \frac{ \mu_{0} I}{2\pi} a ln(\frac{s+a}{s})$$ But it's...
  10. astrocytosis

    Induced current in a loop of wire when straight wire is cut

    Homework Statement A square loop, side a, resistance R, lies a distance s from an infinite straight wire that carries current I (pointing to the right). Now someone cuts the wire, so I drops to zero. In what direction does the induced current in the square loop flow, and what total charge...
  11. astrocytosis

    Eigenvalues and eigenvectors of a Hamiltonian

    I lost a negative sign in the determinant. That will teach me not to skip steps :P Also, it's just ##\sqrt{2} \epsilon##
  12. astrocytosis

    Eigenvalues and eigenvectors of a Hamiltonian

    Homework Statement The Hamiltonian of a certain two-level system is: $$\hat H = \epsilon (|1 \rangle \langle 1 | - |2 \rangle \langle 2 | + |1 \rangle \langle 2 | + |2 \rangle \langle 1 |)$$ Where ##|1 \rangle, |2 \rangle## is an orthonormal basis and ##\epsilon## is a number with units of...
  13. astrocytosis

    Magnetic field inside and outside of a magnetized cylinder

    $$\vec J = [0 - \frac {\partial } {\partial s} (ks) ] \hat \phi = -k \hat \phi$$ so the terms cancel after all. Thanks!
  14. astrocytosis

    Magnetic field inside and outside of a magnetized cylinder

    Since the field outside of a solenoid is zero, only the shells with radius greater than s contribute. So the limits of integration are actually from s to R. And since K is on the surface, s=R and $$B_{K}=\mu_{0)kR$$. This almost gets me to the correct answer except I end up with $$\mu_{0)kR +...
  15. astrocytosis

    Magnetic field inside and outside of a magnetized cylinder

    This is my new integral with In = Jds $$ \mu_{0} \int_0^s J ds $$ $$= \mu_{0} \int_0^s k ds$$ $$ = \mu_{0} ks$$ and the contribution due to K with nI = K is $$ B = \mu_{0} nI =\mu_{0} K = \mu_{0} ks $$
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