Eigenvalues and eigenvectors of a Hamiltonian

AI Thread Summary
The discussion focuses on finding the eigenvalues and eigenvectors of a Hamiltonian for a two-level system, represented by a specific matrix form. The initial matrix representation of the Hamiltonian is incorrectly calculated, leading to confusion about the eigenvalues. After realizing a miscalculation in the determinant, the correct eigenvalues are identified as ±√2 ε. The participants emphasize the importance of careful calculation and notation in deriving the correct results. Accurate understanding of the Hamiltonian's matrix representation is crucial for solving similar problems in quantum mechanics.
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Homework Statement



The Hamiltonian of a certain two-level system is:

$$\hat H = \epsilon (|1 \rangle \langle 1 | - |2 \rangle \langle 2 | + |1 \rangle \langle 2 | + |2 \rangle \langle 1 |)$$

Where ##|1 \rangle, |2 \rangle## is an orthonormal basis and ##\epsilon## is a number with units of energy. Find its eigenvalues and eigenvectors (as linear combinations of ##|1 \rangle, |2 \rangle##). What is the matrix H representing ##\hat H## with respect to this basis?

Homework Equations



N/A?

The Attempt at a Solution


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This problem seems like it should be simple but I think I'm having trouble internalizing the notation. I know each bracket pair represents the 11, 12, 21, 22 components of the matrix, so I thought H should be\begin{bmatrix}
\epsilon & \epsilon \\
\epsilon & -\epsilon
\end{bmatrix}

then I tried to find the eigenvalues the usual way by subtracting ##\lambda I## and taking the determinant of\begin{bmatrix}
\epsilon - \lambda & \epsilon \\
\epsilon & -\epsilon- \lambda
\end{bmatrix}
but I ended up with an expression that implies ##\lambda = 0##

$$-\epsilon^2 + \lambda^2 + \epsilon^2 = 0$$

so I must be misunderstanding something.

EDIT: I miscalculated the determinant, so my answer is actually plausible, but would still appreciate confirmation that this is correct

$$\lambda = \pm \frac{1}{\sqrt{2}} \epsilon$$
 
Last edited:
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Are you sure you wrote that last equation as you intended?
 
I lost a negative sign in the determinant. That will teach me not to skip steps :P Also, it's just ##\sqrt{2} \epsilon##
 
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