Recent content by Badgerspin
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Convergence Tests: Help Setting Up Problem & Deriving Limit
Disregard. I solved it. If anyone saw this and was curious about it, here are the answers. http://i8.photobucket.com/albums/a3/Bivouac/Picture5.png?t=1292032194- Badgerspin
- Post #2
- Forum: Calculus and Beyond Homework Help
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Convergence Tests: Help Setting Up Problem & Deriving Limit
Generally when I post, it's with a specific problem. However in this case, the issue I'm running into is that I don't even have the slightest idea of how to even setup the problem to attempt it. Honestly, I can't seem to find this anywhere in my book and I'm not sure what's really being asked...- Badgerspin
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- Convergence
- Replies: 1
- Forum: Calculus and Beyond Homework Help
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Polar Coordinates: Arc length of two overlapping curves
This question may be something of a dumb one. I feel I should know this, but well, I don't. I'm being asked to find the perimeter inside of the curve r=15sin(theta) and outside of r = 1 Setting up the equation I can do. If it were just an indefinite integral, this would be cake. My...- Badgerspin
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- Arc Arc length Coordinates Curves Length Overlapping Polar Polar coordinates
- Replies: 1
- Forum: Calculus and Beyond Homework Help
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In dealing with differential equations
fzero, I punched in -5/3 and it said it was correct. When you say different initial conditions, what condition are you talking about? I'm not quite following that.- Badgerspin
- Post #5
- Forum: Calculus and Beyond Homework Help
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In dealing with differential equations
It's still not letting me enter in a variable as a solution. I worked it out as shown (thank you). So: k = (ke^(3/7t) - 5)/3 or working with k = e^c ((k^3)e^(3/7t)-5)/3 In either case, it's still not letting me enter in any variables. If there's a solution to this problem that's all...- Badgerspin
- Post #3
- Forum: Calculus and Beyond Homework Help
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In dealing with differential equations
Ok, I've been working this one out for a while, and I just can't seem to get it. I'm looking for the condition such that x(t)=k (where in our class, K generally equals e^c) The initial equation is as such: 7t^2(dx/dt)+3x+5=0 I've worked the equation down to two different forms: x...- Badgerspin
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- Differential Differential equations
- Replies: 5
- Forum: Calculus and Beyond Homework Help
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Solving for Y in a differential equation
My mistake, that should be secø, not sec^2ø. Also, thank you. We haven't gone that far in my class as far as I recall, but this book has a tendency to place equations in earlier sections that are not covered until later sections.- Badgerspin
- Post #3
- Forum: Calculus and Beyond Homework Help
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Solving for Y in a differential equation
I'm sure there's something very simplistic I'm overlooking in this one. That generally tends to be the case, but for the life of me, I can't seem to find it. The following equation is what I started with: dy/dø = [(e^y)(sin^2ø)]/(y*sec^2ø) I have it worked down to the following...- Badgerspin
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- Differential Differential equation
- Replies: 2
- Forum: Calculus and Beyond Homework Help
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In dealing with trigonometric substitution and integration
My problem is that I really don't know how they went from 2 to pi/3 and √2 to pi/3. I'm well aware of what substitution I needed to use. I have no idea what sec(ø) does to help answer this. This is probably basic trig, but I'm finding that there are a lot of things in basic trig that I never...- Badgerspin
- Post #3
- Forum: Calculus and Beyond Homework Help
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In dealing with trigonometric substitution and integration
Here's the equation: ∫(sqrt(2),2) (1/(x^3*sqrt(x^2 - 1)) I have the entire indefinite integral worked down to this (using x = a*secø): ø/2 + 1/4 * sin2ø Now I have the answer book, so I know that's right so far. What I don't understand is how it converted the points of the integral...- Badgerspin
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- Integration Substitution Trigonometric
- Replies: 3
- Forum: Calculus and Beyond Homework Help
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Derivatives of partial fractions
I'm having issue with one problem. We're asked to break down the problem into partial fractions to solve for the integral. Well, I'm stuck on one. I'm being asked for the values of A, B, and C for the following problem. ∫((9x^2+13x-83)/((x-3)(x^2 + 16)))dx I can get it worked down...- Badgerspin
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- Derivatives Fractions Partial Partial fractions
- Replies: 1
- Forum: Calculus and Beyond Homework Help
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What is the Limit of (2x)*[(ln(9)+1)/(ln(13x)+1)] as x approaches infinity?
Ug, please disregard. The format I was given really didn't clarify that everything attached was an exponent to (2x). A friend of mine just pointed that out to me. I feel slightly embarrassed. In my own defense (the images didn't work at my university, so I started with the text versions), I...- Badgerspin
- Post #7
- Forum: Calculus and Beyond Homework Help
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What is the Limit of (2x)*[(ln(9)+1)/(ln(13x)+1)] as x approaches infinity?
Yes, I started with the right expression. The initial expression you posted (Which by the way, I'd like to learn how to do that. It's much neater and easier to read.) looks exactly like what I was given. Thank you for your help. I really wanted to be sure it wasn't me that was doing something...- Badgerspin
- Post #5
- Forum: Calculus and Beyond Homework Help
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What is the Limit of (2x)*[(ln(9)+1)/(ln(13x)+1)] as x approaches infinity?
I did similar to as the poster above did. Remove the constants and set them aside. I'm not seeing how the answer can be anything but infinity, yet the system continually tells me it's wrong. My time expires in a few hours, and I have other work to do. I'm trying to see at this point if the...- Badgerspin
- Post #4
- Forum: Calculus and Beyond Homework Help
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What is the Limit of (2x)*[(ln(9)+1)/(ln(13x)+1)] as x approaches infinity?
I've been having problems with evaluating this one limit. Everytime I work it out, or rework it, I keep getting infinity. It's a webwork problem for my calc 2 class, and each time I submit the answer, it tells me I'm wrong. I plugged it into wolfram as well to confirm, and it tells me infinity...- Badgerspin
- Thread
- Limits
- Replies: 6
- Forum: Calculus and Beyond Homework Help