Recent content by Bardia Sahami

I would use node analysis instead of mesh, as you got only 2 nodes, but 5 meshes. There are two ways to use the node analysis. 1. Consider Vb as ground and write KCL for both A and C nodes. Also write the equation for Va and Vc (which is Va - Vc = 5i where i=Vc/5). 2. Or you can easily consider...

Would you please explain this part?

It would. I actually realized the issue. So basically, in order to create the Thevenin/Norton circuit, you have two find at least two of these: Req/Vth/In. As you stated, Vth is -2Vs obviously. We had problem finding In. But for Req, we turn off the independent sources in the circuit, so once...

Still considered linear. Op amp can be replaced with a VCVS element (Dependent Voltage Source).

Hi. Let's say we have a circuit like that, and we want to find the Thevenin/Norton circuit from a and b points. So for Vth, we calculate the Voc, in which we remove the 2K ohm resistor and calculate the Voc. I calculated it correctly. But I have problem in calculating the Norton current. So in...

Yea same. :) Well, by "simple" I meant it doesn't have capacitor and/or inductor.

Ohhhhhhh, yea. Thanks. I finally realized. Also thanks Berkeman for helping me out. This can be closed I guess.

Would you explain this part please? Why the other part is 2x the first block network?

Any helps?

I don't know. Something like ~5.4 (or less)??

Well, I see a n*2.4 (n*12/5) in my calculations..

*Shrugs* I tried to solve it in another way, but I realized it was also incorrect, I don't know..

Hmmm.. Seems to be incorrect.

I guess I got the idea of your hint, but I'm not sure if it's correct. So if we only consider the resistance value of the first block (n=0 only) as R, in n=1 circuit (first and second blocks only), we have 2R parallel with the first block (R), so we get something like And Req = 1/R + 1/2R +...

Yea, I tried to find a pattern with n=1 (the first block), n=2 (first and second blocks), n=3 and n=4, but it didn't have any kinds of patterns/valid sequences. Well, once n tends to infinite, the resistance value is so high that can be considered as an open circuit. The thing is, it's possible...