Recent content by bengt2665

Just figured it out... we know that m1g=4 and m2g=4 => m1 = 4/g, m2 = 4/g So in the end, after substituting in 1 and 2 we get 1) T1 - 2 = (4/g)a 2) -T1 + 4 = (4/g)a By adding these 2 equations (to get rid of the T) we end up with 2 = 8a/g which gives a = g/4.

This doesn't really help me understand... I end up having 2 equations: 1) T - Ff = ma 2) -T + mg = ma Then I end up with mg - Ff = 2ma (by combining 1 and 2) and I'm stuck there.

The weight of the cart is 4 N. The weight of the hanging mass is 4 N. Friction of the cart on the track is a constant force of 2 N magnitude. The mass of the string, the mass of the pulley, and the friction of the pulley can be neglected. What is the magnitude of the acceleration of the cart...

1. A stone is thrown horizontally from the top of a 20 m high tower. It strikes the ground at an angle of 45 degrees. With what speed was it thrown? I'm having trouble with this problem, any help would be greatly appreciated. This is what I have: I know that Vox = Vo cos 45 and that...