Recent content by BigJon

Thanks! yeah, i knew it wasnt right the gal->mL i was just short on time and yeah i left off days, because i was going to convert it later to hours since I am comparing it to some charts for a lab report

Homework Statement Basically I'm given a feed flowrate - 70,000 gal/day I know the weight percent is 35% and the component is Triethylene Glycol - density - 1.255g/ml Homework EquationsThe Attempt at a Solution So i did this 70,000 gal/day * .35 * (.0378mL/1gal)* 1.255g/mL = g of Triethylene...

Homework Statement Moon's gravity is 5.31ft/sec^2 An object has the weight of 3.5 lb-f on the moon. What is its lb-m What is the lb-m and lb-f on Mars with gravity of 12.1 ft/sec^2. Homework Equations w=mg=mg/gc gc= gravitational constant----> 32lbm*ft/sec^2 for earth The...

Homework Statement a heavy object of mass m is suspened in a room through a linear spring whose spring constant is k. Initially the object is suspported so that the spring is at its free length (neither strecthed/compressed) which is take to be x=0. At time zero the support is removed and...

It worked lol :P

25x^2-10x-200y-119=0 Should i divide both sides by 25 and then put y and constant to right side of equation and then complete the square?

No I am getting 1/27 when i divided the highest terms

Okay i worked it again and tried to follow what you said hopefully I attached a pic of my work, srry for the sloppiness :P

Sorry i attached a pic of the actual prob if that would help Also i don't see where i have that problem i took (3n+1)! to (3n!)(3n+1)

Forgot to mention on my calculator it says the limit goes to infinity but i need to know how to actually show steps, etc

∞ Ʃ (((n)!)^3)/(3(n))! Use the ratio test to solve n=1 So first i put it into form of (n!)^3/3n!, then applied ratio test. from ratio got ((n+1)!)^3/(3n+1)! times (3n)!/(n!)^3 from here I am on shaky ground i go reduce the terms to (n!)^3(n+1)^3/(3n!)(3n+1) times...

My question is to find the resultant just take the x,y components of each force, find the magnitude by squaring them and taking the square root. My question is after doing that how would i find the perpendicular and horizontal distances. My teacher put a study guide for our test and it said...

Yes so i just sum all those multiply by (1/8) and that's it? I am just trying to make sense of my teachers notes.

When i get to terms that cancel out, what do i do to solve that's where I am confused. my teacher never explained exactly what to do

∞ Ʃ 1/(n(n+8)) n=1 So i used partial fractions and got (1/8)/(n) - (1/8)/(n+8) From there i pulled out the 1/8 so now my equation is ∞ (1/8) Ʃ (1/n)-(1/(n+8)) n=1 So from here do i just start doing like s1= (1/8)(1-1/9), s2=(1/8)(1/2-1/10) to find...