Mass of one component in two component w/feed flowrate

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SUMMARY

The discussion centers on calculating the mass of Triethylene Glycol from a given feed flowrate of 70,000 gallons per day with a weight percent of 35%. The correct formula for determining the mass is established as 70,000 gal/day * 0.35 * (0.0378 mL/1 gal) * 1.255 g/mL. However, the initial conversion from gallons to milliliters was incorrectly approached, as 1 gallon equals approximately 3,785 mL, not 0.0378 mL. Additionally, the units of the final answer must include "day" to maintain dimensional consistency.

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Homework Statement


Basically I'm given a feed flowrate - 70,000 gal/day
I know the weight percent is 35% and the component is Triethylene Glycol - density - 1.255g/ml

Homework Equations

The Attempt at a Solution


So i did this

70,000 gal/day * .35 * (.0378mL/1gal)* 1.255g/mL = g of Triethylene Glycol

Is this correct, i know the gal->mL might be wrong but is the basic setup correct using wt%?
 
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You soft of have the right idea. But, "gal->mL might be wrong" is a gross understatement. Do you really think that 1/30 of a ml is the same as one gallon (1 gallon is close to 4 liters)? And the units of your answer are incorrect. What happened to "day."

Chet
 
Thanks! yeah, i knew it wasnt right the gal->mL i was just short on time and yeah i left off days, because i was going to convert it later to hours since I am comparing it to some charts for a lab report
 

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