Recent content by blayman5

Homework Statement A projectile of mass 5 kg is fired with an initial speed of 80 m/s at an angle of 75◦ with the horizontal. At the top of its trajectory, the projectile explodes into two fragments of masses 3 kg and 2 kg . The 2 kg fragment lands on the ground directly below the point...

Ok, thanks!

Ha, that's really weird. No, I go to Connally. I don't know if the angle would matter or if it just would be the velocity itself. I got it wrong when I did it.

Homework Statement A ball of mass 0.4 kg is initially at rest on the ground. It is kicked and leaves the kicker’s foot with a speed of 5.0 m/s in a direction 60◦ above the horizontal. The magnitude of the impulse k~Ik imparted by the ball to the foot is most nearly The Attempt at a...

Remember that F=Wx, so find the work done by kinetic energy N * m = (kg *(m^2/s^2) )/ 2 N = (kg *(m^2/s^2) )/ 2 m N = (kg *(m/s^2) )/ 2 Use the distance given to find the force

I got it: T-W =(mv^2)/L mgL(1-cosO)=(mv^2)/2 T=(mv^2)/L+W mv^2=2mgL(1-cosO) T=(2mgL(1-cosO))/L+W T=(2W(1-cosO))/+W T=2W-2WcosO+W T=3W-2WcosO T=W(3-2cosO) Thanks

Homework Statement I have to prove in a conservation of energy question T-W =(mv^2)/L mgL(1-cosO)=(mv^2)/2 mg=W T=W(3-2Cos0) How could I go about starting this?

I have to prove in a conservation of energy question T-W =(mv^2)/L mgL(1-cosO)=(mv^2)/2 mg=W T=W(3-2Cos0) How could I go about starting this?

ok i got gsin0 and it was correct. Thanks

there is the tension and its components and mg as the forces on the ball. The component TsinO would be the tangential force. Tcos0=mg. T=mg/cos0 Tsin0=ma (mg/cos0)(sin0)=ma Where did I misinterpret the problem? The velocity at point Q is 0m/s

oh ok i did the process and i got a=gtan0. If the string broke at point Q, would it undergo projectile motion with a horizontal initial velocity?

I did TcosO-mg=ma T=mg+ma/cos0 but there is no mass given in the problem

T=mg mgcos0=ma a=gcos0?

The forces acting on the ball are the tension and the mg. TcosO=mg+ma. Since I do not know the tension, how can I solve for tangential acceleration?

Ah, there would be tangential acceleration. How would you go about finding it? The initial steps.