What is the magnitude of the impulse imparted by a kicked ball to the foot?

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The discussion focuses on calculating the impulse imparted by a kicked ball to the foot, with a mass of 0.4 kg and a final speed of 5.0 m/s at a 60-degree angle. The impulse is determined using the formula I = change(p) = mvf - mvi, resulting in an impulse of 1 N*s. Participants express confusion about the relevance of the angle in the calculation, with one confirming that the angle does not affect the impulse value. The conversation includes a light-hearted exchange about coincidentally posting similar problems. Ultimately, the correct impulse calculation is confirmed to be 1 N*s, regardless of the angle.
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Homework Statement


A ball of mass 0.4 kg is initially at rest on the
ground. It is kicked and leaves the kicker’s
foot with a speed of 5.0 m/s in a direction 60◦
above the horizontal.
The magnitude of the impulse k~Ik imparted
by the ball to the foot is most nearly



The Attempt at a Solution



I=change(p)
pf-pi
mvf-mvi
(0.4)(5cos60)-(0.4)(0)
=1 N*s
Where did I go wrong in the problem?
 
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WOW how weird we posted the same problem near the same time as each other o_O

Do you go to Bellaire by any chance?

(BTW check my topic, I'm not sure I'm right but I did it differently than you)
 


Ha, that's really weird. No, I go to Connally. I don't know if the angle would matter or if it just would be the velocity itself. I got it wrong when I did it.
 


Ok, I was right, just ignore the angle :D
 


Ok, thanks!
 

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